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BartSMP [9]
3 years ago
7

miss. Nikkel want to divide her class of 23 students into 4 equal teams.is this reasonable?why or why not

Mathematics
2 answers:
ella [17]3 years ago
6 0
No, because if you divide 23 / 4, you get 5.75. You can't get 0.75th of a kid. So it is not reasonable, because it is a decimal, and not a whole number.

Hope this helped! ☺♥
bearhunter [10]3 years ago
5 0
It's impossible to get good quantity of command with the total quantity of 23.
So possible numbers of commands are 3 commands, 4 commands, 5 commands.
3 commands:  There are 7 students inside each and 2 students out of commands.
4 commands: There are 6 students inside each and there is no one students inside one command.
5: commands: There are 5 students inside each and there is no two students inside one command.
So 4 commands will be reasonable for the 23 students. But one command still without 1 student.
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It is estimated that approximately 8.23% Americans are afflicted with diabetes. Suppose that a certain diagnostic evaluation for
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The probabilities in this problem are given as follows:

a) False positive: 0.0321 = 3.21%.

b) Diagnosed as not having diabetes: 0.8872 = 88.72%.

c) Actually has diabetes, if diagnosed as not having: 0.0019 = 0.19%.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is given as follows:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which the parameters are described as follows:

  • P(B|A) is the probability of event B happening, given that event A happened.
  • P(A \cap B) is the probability of both events A and B happening.
  • P(A) is the probability of event A happening.

For item a, we have that:

  • 100 - 8.23 = 91.77% of the people do not have diabetes.
  • Of those, 3.5% are diagnosed with diabetes.

Hence the probability of a false positive is given as follows:

p = 0.9177 x 0.035 = 0.0321 = 3.21%.

For item b, the percentage of people who is not diagnosed as having diabetes is divided as:

  • 96.5% of 91.77% (do not have diabetes).
  • 2% of 8.23% (have diabetes).

Hence the probability is:

P(A) = 0.965 x 0.9177 + 0.02 x 0.0823 = 0.8872 = 88.72%.

For item c, we find the conditional probability, as follows:

P(A \cap B) = 0.02 \times 0.0823 = 0.001646

Then:

P(B|A) = 0.001646/0.8872 = 0.0019 = 0.19%.

More can be learned about probabilities at brainly.com/question/14398287

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1 year ago
Use a = -2, b = - 3, and c = 6 to write an expression that has a value of 12.
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a negative times a negative = a positive

so (a * b) + c = 12

(-2 * -3) +6 = 12

6+6 = 12

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Answer:

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Add 4 to both sides

18y = 4

Divide both sides by 18

A possible solution is :

y = (2/9)

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