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kkurt [141]
3 years ago
9

Jdr-wivg-vmbco.me a.nd jo.in fa.st...go.ogle me.et​​​

Mathematics
2 answers:
miskamm [114]3 years ago
7 0

Answer:

Step-by-step explanation:

K

Nastasia [14]3 years ago
3 0

Step-by-step explanation:

I'm coming.... Wait a minute

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The landscaper charges a rate of $40 per hour to plant trees.Amelia paid a total of $725 for the trees and for the landscaper to
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23.5 hours is the anser yeteressdfdsfsjufrhhmrgijfjfxkjvnrtjeigrjiegre

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3 years ago
Find the solution by elimination method. <br>Please Help. ​
love history [14]

Answer:

I'm newbie here

Step-by-step explanation:

Elimination Method.

4x + 6/y = 15 → step 1

6x - 8/y = 14 → step 2

so,

4x + 6/y = 15 |×6|

6x - 8/y = 14 |×4|

24x + 6/y(6) = 90

24x - 8/y(4) = 56

24x + 36/y = 90

24x - 32/y = 56

____________ _

68/y = 34

68 = 34y

34y = 68

y = 2

subsitution y = 2 to..

4x + 6/y = 15

4x + 6/2 = 15

4x + 3 = 15

4x = 12

x = 3

So, for x is 3, and for y is 2

5 0
3 years ago
Read 2 more answers
An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell
mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

\overline{x} = \frac{34+40+46+49+61+64}{6} = 49

Sample standard deviation:

s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.0.150

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. So

M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0
3 years ago
GUYS HELP please i dont know what to answer
grandymaker [24]

Answer:

2nd one : y = -4/x

3rd one : y + x/2 = 9

4th one

5th one : y = x^2

6th : 5.8x - y = 2.3

Step-by-step explanation:

Not sure about these. You might want to wait for another person to answer

Have a nice day!

7 0
3 years ago
Determine how many books are in the cooking category
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Depends on how much people want there too be cooking books

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