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Dimas [21]
3 years ago
5

Helppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

I dont know

Step-by-step explanation:

I dont know sorry

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Use the figure to complete the proportion.
MAVERICK [17]

Answer:

BE / AB = <u>HE</u> / AH

Step-by-step explanation:

AE is angle bisector

BE / HE = AB / AH

BE / AB = HE / AH

6 0
3 years ago
Find the sum 1/2 + 3/8
Stels [109]

Answer: 7/8

Step-by-step explanation:

The easiest way to do this is to find a common denominator, so first we find out 2 times how much equals 8? 2x4 = 8. So with 8 being our common denominator, we have to multiple 4 to every number in the fraction 1/2. So 1x4 = (4/8) = 2x4. Then you just add the top numbers, so 4 + 3 = 7 and keep the denominator. 7/8.

5 0
2 years ago
Read 2 more answers
Complete the multiplication: AB. <br><br> A. <br> B. <br> C. <br> D.
Firdavs [7]
These array of numbers shown above are called matrices. These are rectangular arrays of number that are arranged in columns and rows. It is mostly useful in solving a system of linear equations. For example, you have these equations

x+3y=5
2x+y=1
x+y=10

In matrix form that would be

\left[\begin{array}{ccc}1&3&5\\2&1&1\\1&1&10\end{array}\right]

where the first column are the coefficients of x, the second column the coefficients of y and the third column is the constants, When you multiple matrices, just multiply the same number on the same column number and the same row number. For this problem, the solution is

\left[\begin{array}{ccc}3*2&0*8\\2*0.6&-1*3\end{array}\right] =  \left[\begin{array}{ccc}6&0\\1.2&-3\end{array}\right]

6 0
3 years ago
The school soccer team buys 3 soccer balls for every 2 players. The school volleyball team buys 7 volleyballs for every 5 player
SSSSS [86.1K]
Soccer buys more; divide each

Soccer- 3/2= 1.5
Volleyball- 7/5=1.4

Soccer buys more balls per player
6 0
3 years ago
Solve the following system of equations.
vodomira [7]

Answer:

a = 6/5

b = 7/8

c = 1/5

Step-by-step explanation:

We want to make two of these equations be in terms of the same variable, so let's solve the first and third  in terms of b.  

5a-24b=-15 -> -3 + 24b/5 = a

48b+35c = 49 -> 49/35 - 48b/35 = 7/5 - 48b/35 = c

Now we can replace the a and c in the second equation and solve for b.

10a+45c=21

10(-3+24b/5)+45(7/5 - 48b/35) = 21

-30 + 48b + 63 - 432b/7 = 21 -> -12 = -96b/7 -> b=7/8

Now we can plug b back into the other two to solve for a and c.  I will leave that to you unless you would like the steps there.

7 0
3 years ago
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