Answer:
a. AB: 3 by 7
b. BA: N by N
c. A^TB: N by N
d. BC: 6 by 3
Step-by-step explanation:
Given



Required
The dimension of the following matrices
As a general rule:
For A * B to be successful, the columns in a must equal the rows in B
Using this rule, we have:

So:




The column numbers of B does not equal the row numbers of A.
Hence, BA does not exist

implies that:
If
, then

So:

The column numbers of A^T does not equal the row numbers of B.
Hence,
does not exist


Rearrange the first system to get x = -3y + 14. Substitute that into the other system.

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Answer:
Length of XM is 5.5 units.
Step-by-step explanation:
Given △XYZ where MZ is the angle bisector of ∠YZX . we have to find the length of XM.
A triangle with vertices X, Y, and Z. Side XZ is base. A line segment drawn from Z to M bisects ∠YZX into two parts ∠YZM and ∠XZM.
YZ=7 units, XZ=11 units and YM=3.5 units
By angle bisector theorem which states that an angle bisector of an angle divides the opposite side in two segments that are proportional to the another two sides of the triangle.
Hence, 
⇒ 
⇒ MX=5.5 units.
Hence, length of XM is 5.5 units.
Answer:
x=−3x−7whatish(−4)
Step 1: Flip the equation.
28ah2istw−3x=x
Step 2: Add 3x to both sides.
28ah2istw−3x+3x=x+3x
28ah2istw=4x
Step 3: Divide both sides by 28h^2istw.
28ah2istw
28h2istw
=
4x
28h2istw
a=
x
7h2istw
Answer:
a=x7h2istw
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