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gregori [183]
3 years ago
12

I need the answer asap2.794 x 10^9

Mathematics
1 answer:
faltersainse [42]3 years ago
8 0

Answer:

2794000000

Step-by-step explanation:

2.794 x 10^9

= 2794000000

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They are about 400cm long just make sure u put that
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3 years ago
The sum of three numbers is 12. The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is
Ede4ka [16]
A suitable calculator can row-reduce the augmented matrix.

first number: 3
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5 0
3 years ago
7 meters/20 minutes= x cm/2 hours
meriva

Answer:4,200

Step-by-step explanation:

4 0
3 years ago
A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019
kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

6\5=\frac{6}{100}=0.06

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

y=14,000*(1-0.06)^x

y=14,000*(0.94)^x

Let us find x by subtracting 2010 from 2019.

x=2019-2010=9

Upon substituting x=9 in our function we will get,

y=14,000*(0.94)^9

y=14,000*0.5729948022286167

y=8021.927\approx 8022

Therefore, the population of fish in 2019 will be 8022.

6 0
3 years ago
What is the average rate of change of the function
Reptile [31]

Answer:

Average rate of change =-35.7084

Step-by-step explanation:

Given function is f(x)=480(0.3)^x and we need to find average rate of change of the function from x=1\ to\ x=5.

Average rate of change =\frac{f(b)-f(a)}{b-a}

So,

here\ b=5\ and\ a=1\\f(5)=480(0.3)^5\\=480\times0.00243=1.1664\\and\\f(1)=480(0.3)^1\\=480\times0.3=144

Average rate of change

=\frac{f(b)-f(a)}{b-a}\\\\=\frac{f(5)-f(1)}{5-1}\\\\=\frac{1.1664-144}{5-1}\\\\=\frac{-142.8336}{4}= -35.7084

Hence, average rate of change of the function f(x)=480(0.3)^x over the intervel x=1\ to\ x=5 is =-35.7084.  

5 0
3 years ago
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