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2 years ago

How much should Jordan budget monthly for an annual expenditure that coast $614.66? * TIMED!

Mathematics

2 answers:

poizon [28]2 years ago

6 0

Answer:

he should budget about $51.22

Step-by-step explanation:

annual mean one year since there is 12 months in a year you would want to divide 12 to $614.66

dlinn [17]2 years ago

3 0

Answer:

i think it's $51.22 Cause it said annual which means one year and it has 12 months so the actual price devide by 12

am not that sure tho cause the question is tricky

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Use integration by parts to find the integrals in Exercise.<br> ∫(x+6)ex dx.

skelet666 [1.2K]

Answer:

$xe^x+5e^x$

Step-by-step explanation:

We have given integral $\int (x+6)e^xdx$

$\int (xe^x+6e^x)dx$

$\int (I_1+I_2)dx$ , here $I_1=xe^x$ and $I_2=6e^x$

Now first integrate $I_1$

So $I_1=\int xe^x$

Integrating by part

$I_1=x\int e^x-\int e^x\frac{d}{dx}x$

$I_1=x e^x- e^x$

$I_2=6\int e^x=6e^x$

So $I=I_1+I_2=xe^x-e^x+6e^x=xe^x+5e^x$

5 0

2 years ago

A family purchased basketball tickets online. The total cost, c, in dollars, of t tickets can be found using the function below.

Reptile [31]

Solution:
C=32.50t+8.50
236=32.50t+8.50
236-8.50=32.50t
227.50=32.50t
227.50/32.50=32.50t/32.50
t=7

The family bought 7 tickets.

3 0

2 years ago

Not sure need help

kvasek [131]

Answer:

X = 3

Step-by-step explanation:

So do 7-2 which equals 5. 5 times 6 because 6 is outside of the parentheses with no symbol, so that means to multiply. That would equal 30. You want your answer to equal 6, so you would want the number inside of the parentheses to be 1, so that 1 times 6 would be 6. 2 x 3 would be sixe, and then 7-6 would equal one. 1 times 6 would be 6. So there is your answer.

4 0

2 years ago

Read 2 more answers

find continued product of (x+y) (x-y) (<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}"

leonid [27]

Answer:

$\large\boxed{(x+y)(x-y)(x^2+y^2)(x^4+y^4)=x^8-y^8}$

Step-by-step explanation:

$(x+y)(x-y)(x^2+y^2)(x^4+y^4)\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\qquad(*)\\\\=\underbrace{(x+y)(x-y)}_{(*)}(x^2+y^2)(x^4+y^4)\\\\=\underbrace{(x^2-y^2)(x^2+y^2)}_{(*)}(x^4+y^4)\\\\=\left((x^2)^2-(y^2)^2\right)(x^4+y^4)\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\underbrace{(x^4-y^4)(x^4+y^4)}_{(*)}\\\\=\left(x^4\right)^2-\left(y^4\right)^2=x^8-y^8$

7 0

2 years ago

Whats 9-14? having trouble on this problem plz help !!!!!

Minchanka [31]

Answer:

Step-by-step explanation:

Count backwards fro. 9 till you subtract 14 answer us -5

7 0

2 years ago