If I understand the question correctly, you can have the same amount of change be two different percentages by having 4 quarters and 100 pennies.
Each quarter is 25%
Each penny is 1%
(am i explaining this right)
3pi/7 < pi/2 because 3/7 < 1/2, and pi/2 is a right angle. Conclusion: the angle opposite side a is an acute angle. In this situation the triangle could be a right triangle, in which case C would be true, but it does not have to be a right triangle, so don´t choose C. Similarly, it could be an acute triangle, in which case B would be true, but it does not have to be, so don´t choose B. Also, A says the angle opposite side a is obtuse, which is false. So don´t choose A. That leaves D, which says the angle opposite side a is acute, which we know is true. So the answer is <span>D. b^2 + c^2 > a^2</span>
Answer:
A shaded region below a dashed line (y <3x-4)
Step-by-step explanation:
For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.
Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.
In this case what we have here is an open region, as the graph below shows.
3x-y>4 =-y>4-3x∴y<3x-4
Setting a value for x
3x-4=0
3x=4
3x/3=4/3
x=4/3 (slope)
(4/3,0)
