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igor_vitrenko [27]
3 years ago
15

Factor the expression using the GCF. 22+11=

Mathematics
1 answer:
bezimeni [28]3 years ago
6 0

ANSWER

the factor <em>will </em>

<em>1</em><em>1</em><em> </em><em>is </em><em>common</em><em> </em><em>in </em><em>both </em><em>the </em><em>given </em><em>term</em>

<em>so,</em><em> </em><em>when </em><em>we </em><em>take </em><em>1</em><em>1</em><em> </em><em>from </em><em>both </em><em>term </em>

<em>it </em><em>will </em><em>left </em><em>with </em><em> </em>

<em>1</em><em>1</em><em>(</em><em> </em><em>2</em><em>+</em><em>1</em><em>)</em><em> </em>

<em>this </em><em>is </em><em>the </em><em>final </em><em>answer</em><em> </em>

<em>hope </em><em>it </em><em>helps </em><em>and </em><em>u </em><em>have </em><em>a </em><em>great</em><em> </em><em><u>day</u></em>

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100 pts
lapo4ka [179]
It’s not 100 points it’s only five points
5 0
2 years ago
An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y
Kay [80]

Answer:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

\bar X_{1}=14 represent the mean for sample 1 (younger)

\bar X_{2}=20 represent the mean for sample 2 (older)  

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=31 sample size for the group 2  

n_{2}=31 sample size for the group 2  

t would represent the statistic

System of hypothesis

We want to test if  that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=31+31-2=60  

Replacing the info given we got:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

6 0
3 years ago
Could someone please help? They don’t need to be solved I just need help with the translating.
Lorico [155]

Answer:

I won't solve i'll translate like you asked

Step-by-step explanation:

13) x - 5 = 21

14) 12 × y = 48

15) b + 10 = 13

If you want I can solve.

HOPE THIS HELPED

5 0
3 years ago
PLEASE HELPP
Igoryamba

Answer:

There are 12 bottles of water in a full pack.

Step-by-step explanation:

12

12

12

11

11

9

-------

67

5 0
2 years ago
1. What is the theoretical probability that the family has two dogs or two cats?
gogolik [260]

let dogs be heads. Let cats be tails. A coin has two sides, in which you are flipping two of them. Note that there can be the possible outcomes  

h-h, h-t, t-h, t-t.  

How this affects the possibility of two dogs & two cats. Note that there are 1/2 a chance of getting those two (with the others being one of each), which means that out of 4 chances, 2 are allowed.  

2/4 = 1/2  

50% is your answer

Heads represents cats and tails represents dogs. There is two coins because we are checking the probability of two pets. You have to do the experiment to get your set of data, once you get your set of data, you will be able to divide it into the probability for cats or dogs. To change the simulation to generate data for 3 pets, simply add a new coin and category for the new pet.

Hope this helps you out!

4 0
3 years ago
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