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igor_vitrenko [27]
3 years ago
15

Factor the expression using the GCF. 22+11=

Mathematics
1 answer:
bezimeni [28]3 years ago
6 0

ANSWER

the factor <em>will </em>

<em>1</em><em>1</em><em> </em><em>is </em><em>common</em><em> </em><em>in </em><em>both </em><em>the </em><em>given </em><em>term</em>

<em>so,</em><em> </em><em>when </em><em>we </em><em>take </em><em>1</em><em>1</em><em> </em><em>from </em><em>both </em><em>term </em>

<em>it </em><em>will </em><em>left </em><em>with </em><em> </em>

<em>1</em><em>1</em><em>(</em><em> </em><em>2</em><em>+</em><em>1</em><em>)</em><em> </em>

<em>this </em><em>is </em><em>the </em><em>final </em><em>answer</em><em> </em>

<em>hope </em><em>it </em><em>helps </em><em>and </em><em>u </em><em>have </em><em>a </em><em>great</em><em> </em><em><u>day</u></em>

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Yuri [45]

Answer:

i am very bad at o math i am only at 8 sorry

Step-by-step explanation:

if you could give me a brainliest.

5 0
2 years ago
Helpppppppppppppppppppp
lesya [120]

Answer:

• An angle

Step-by-step explanation:

A line, line segment, ray are named by two points

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3 0
2 years ago
The slope field for the differential equation dy/dx=(3y)/(xy+5x) will have vertical segments when
Inessa05 [86]

Answer:

E) x=0 or y=-5

Step-by-step explanation:

The slope field will have vertical segments when dy/dx is undefined, that is, dy/dx is a division by 0.

We have that

dy/dx=(3y)/(xy+5x)

So the slope field will have vertical segments when

xy + 5x = 0

x(y + 5) = 0

This is when x = 0 or y = -5.

So the correct answer is:

E) x=0 or y=-5

3 0
3 years ago
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
PLEASE HELP Find the product. (n³)² • (n⁵)⁴​
Papessa [141]

Answer:

n^{26}

Step-by-step explanation:

Raising something to a power to a power simply simply multiplies the two exponents

(n^3)^2 = n^6

(n^5)^4 = n^20

Multiplying two numbers with the same base (n) will add the exponents

n^6 x n^20 = n^26

5 0
3 years ago
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