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3 years ago

PLS HELP ASAP I DONT HAVE TIME IT ALSO DETECT IF ITS RIGHT OR WRONG!!

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

Hoped I helped! Im Eve btw. Have a great day and consider marking this brainiest if you do thank you in advanced!

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What is the nth term of the sequence? 4, 2, 0, –2, ..

tatuchka [14]

' n ' the 'n'th term

1    4
2    2
3    0
4 -2 .

In general, the 'n'th term of the sequence is A(n) = 6 - 2n .

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3 years ago

Please help me out!!! :)

Olin [163]

it would be > because the square root of 2 is more than 1.

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4 years ago

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

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3 years ago

What is 1x + 3x when x=1

rodikova [14]

Answer:

x therefore will be equal to 4

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PLEASE HELP !!! :) :( Please!

Ludmilka [50]

Y= 1x + 8
both is increasing by one

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3 years ago