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Ede4ka [16]
3 years ago
10

Hayk was walking around the cross-shaped pool with 10m-long sides , while Karlen was swimming in it. During the time Hayk got fr

om point A to point B, Karlen swam diagonally from point B to A and back.
By what percent did the distance covered by Karlen exceed that of Hayk ? (round your answer to the nearest tenth)

Mathematics
1 answer:
Fed [463]3 years ago
5 0

Answer:

5,41%

Step-by-step explanation:

Remark

It's hard to interpret what % increase means. I'm going to work first with the actual increase and then I'll give the % increase. The answer I give will likely be in your choices, but it could still be incorrect.

Givens

Walking distance from A to B = 10 units down + 10 units east + 10 units down + 10 units east + 10 units down + 10 units east = 60 units.

Swimming distance = 2*sqrt(10^2 + 30^2) = 63.25 units.

Solution

The difference = 63.25 - 60 = 3.25

The % increase = (3.25/60)*100 = 5.41%

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