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Ede4ka [16]
3 years ago
10

Hayk was walking around the cross-shaped pool with 10m-long sides , while Karlen was swimming in it. During the time Hayk got fr

om point A to point B, Karlen swam diagonally from point B to A and back.
By what percent did the distance covered by Karlen exceed that of Hayk ? (round your answer to the nearest tenth)

Mathematics
1 answer:
Fed [463]3 years ago
5 0

Answer:

5,41%

Step-by-step explanation:

Remark

It's hard to interpret what % increase means. I'm going to work first with the actual increase and then I'll give the % increase. The answer I give will likely be in your choices, but it could still be incorrect.

Givens

Walking distance from A to B = 10 units down + 10 units east + 10 units down + 10 units east + 10 units down + 10 units east = 60 units.

Swimming distance = 2*sqrt(10^2 + 30^2) = 63.25 units.

Solution

The difference = 63.25 - 60 = 3.25

The % increase = (3.25/60)*100 = 5.41%

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(x+23)+(2x+4)=180

x+23+2x+4=180

3x+27=180

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3x=153 /: 3

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Which of the following is a composite number between 40 and 50?
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Please answer all of these for 50 points!!!
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Line PQ = Line XY

Line QR = Line YZ

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2x-y=-1 , 3x-y=2 solve by substition
Mazyrski [523]

Answer:

x = 3, y = 7

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Step-by-step explanation:

We are given the system of equations below:

\large{ \begin{cases} 2x - y =  - 1 \\ 3x - y = 2 \end{cases}}

We are required to solve the system by substitution method. What we have to do is to isolate either x-term or y-term so we can use the method. I will be isolating y-term because it is faster due to having 1 as a coefficient.

By isolating y-term, just pick one of the given equations to isolate. No need to isolate the whole system. (I will be isolating y-term of the first equation.)

\large{ \begin{cases} y=  2x + 1\\ 3x - y = 2 \end{cases}}

Then we substitute y = 2x+1 in the second equation.

\large{3x - (2x + 1) = 2}

Use the distribution property.

\large{3x - 2x - 1 = 2}

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\large{x = 2 + 1} \\  \large{x = 3}

Since we are solving a system of equations. We have to solve for both x-value and y-value to complete. We have already found x-value, but nor y-value yet. Therefore, our next step is to substitute the value of x that we solved in any given equations. It's recommended to substitute in an equation that doesn't have high coefficient value. So I will be substituting x = 3 in the first equation.

\large{2x - y =  - 1}  \\  \large{2(3) - y =  - 1} \\  \large{6 - y =  - 1}

Isolate and solve for y-term.

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Since we substitute x = 3 and get y = 7. We can write in ordered pairs as (3,7)

Hence, the solution is (3,7)

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3 years ago
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