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3 years ago

I bet no one can solve this (+)^=∑24_(=0)^▒〖(¦) ^ ^(−) 〗 HAHAHAAAAAAAAAAAAA

Mathematics

2 answers:

umka21 [38]3 years ago

8 0

What's this? Cute. Thnx for the freee pointttssss <3

puteri [66]3 years ago

5 0

Answer:

free points nice

Step-by-step explanation:

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Find x and y in the figure

Grace [21]

Answer:

x=10, y=25

Step-by-step explanation:

First, in a trapezoid, the two angles on the same leg (the legs are the opposite sides that are not parallel) add up to 180 degrees. Therefore, 4y as well as (2y+3x) are supplementary. We can write this out as

4y + (2y+3x) = 180

6y+3x = 180

Next, the angles of a triangle add up to 180 degrees. Therefore, as the angles 2y, 4y, and (5x-20) make up a triangle, they add up to 180 degrees. We can write this as

4y + 2y + (5x-20) = 180

6y + 5x -20 =180

Our two equations are thus

6y + 5x - 20 = 180

6y + 3x = 180

If we subtract 6y from both sides in each equation, we can say

5x - 20 = 180-6y

3x = 180-6y

Therefore, we can write

5x-20 = 180-5y = 3x

5x-20=3x

subtract 3x from both sides to make all x variables on the same side

2x-20 = 0

add 20 to both sides to isolate the x and its coefficient

2x = 20

divide both sides by 2 to isolate x

x = 10

Therefore,

x = 10

6y + 3x = 180

6y + 30 = 180

subtract 30 from both sides to isolate the y and its coefficient

6y = 150

y = 25

5 0

3 years ago

Darcy house is 6 times as far from school as her friends house. if her friends house is 3/4 mile from school how many miles from

laiz [17]

3.75 miles because 3/4 is .75 in money and the 3 is howm many miles

6 0

3 years ago

On a piece of paper, use a protractor and a ruler to construct two equilateral triangles: one with a side length of 2 inches and

Monica [59]

Answer:

Answer:

(B)

Step-by-step explanation:

We have to construct two equilateral triangles that is one with the side length of 2 inches and the another triangle with side length of 3 inches.

Now, both the triangles are equilateral triangles, thus they have same shape.

Also, both triangles have different side lengths, one having 2 inches and another having 3 inches, thus they have different size.

Hence, the true statement about the two triangles is:

The two triangles are the same shape but not the same size.

Therefore, option B is correct.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the slope of the line passing through the points (0, 4) and (-8, -1)?

Bas_tet [7]

Answer:

0.625

Step-by-step explanation:

Given the points :

(0, 4) and (-8, -1)

x1 = 0 ; y1 = 4

x2 = - 8 ; y2 = - 1

Slope, m = rise / run

Rise = y2 - y1 = - 1 - 4 = - 5

Rise = x2 - x1 = - 8 - 0 = - 8

The slope, m = - 5 / - 8

Slope, m = 0.625

7 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago