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3 years ago

identify an equation in point slope form for the line perpendicular to y=-2x+8 that passes through (-3,9)

Mathematics

1 answer:

Svetach [21]3 years ago

6 0

Answer:

y - 9 = 1/2(x + 3)

Step-by-step explanation:

find the slope that is perpendicular to line y = -2x + 8, which is the negative reciprocal slope: 1/2

substitute the new slope 1/2 and the given/known point (-3, 9) into the point-slope form:

=> y - 9 = 1/2(x - (-3)) => y - 9 = 1/2(x + 3)

point-slope form:

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Answer:

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Step-by-step explanation:

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3 years ago

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d1i1m1o1n [39]

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3 years ago

Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uz lz∫uxlx∫uyly????y

SSSSS [86.1K]

Answer:

X from 0 to 21

Y from 0 to 7

Z from 0 to 3

Step-by-step explanation:

Since we are being asked by the integration limits in first octant (positive x, positive y and positive z) we need to know where does the plane intersect this axes. For this we have:

for x=0 and y=0

7z=21

z=3

for x=0 and z=0

3y=21

y=7

for z=0 and y=0

x=21

This means that the integration limits are:

X from 0 to 21

Y from 0 to 7

Z from 0 to 3

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4 years ago