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slega [8]
3 years ago
7

A circular flower bed is 24 m in diameter and has a circular sidewalk around it 3 m wide. Find the area of the sidewalk in squar

e meters
Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

120.105m^2

Step-by-step explanation:

Given data

Diameter of circular bed=  24+3m = 27m

radius= 27/2= 13.5 m

Diameter of side walk = 12

radius= 24= 12 m

Hence the area of the sidewalk is

Area= area of circular bed- area of side walk

Area=πR^2-πr^2

Area=π(R^2-r^2)

Area=π(13.5^2-12^2)

Area= 3.14(182.25-144)

Area= 3.14(38.25)

Area=120.105m^2

Hence the area of the side walk is 120.105m^2

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Answer:

Please check the explanation.

Step-by-step explanation:

Given the points

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When we plot P1(3, 2) and P2(6, 8), we determine the line segment P1P2.

The direction of the segment is from P1 to P2.

Determining the length of the segment P1P2.

\:l=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

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  =3\sqrt{5}

Thus, the length of the segment is:

\:\:\:l=3\sqrt{5}

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Given the points

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  • P2(6, 8)

Finding the slope between P1(3, 2) and P2(6, 8)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(3,\:2\right),\:\left(x_2,\:y_2\right)=\left(6,\:8\right)

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Using the line point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 2 and the point (3, 2)

y-2=2\left(x-3\right)

Add 2 to both sides

y-2+2=2\left(x-3\right)+2

y=2x-4

Thus, the equation of a line containing the line segment P1P2 is:

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