A city council organized a marathon race to promote good health. There were 3 times as many female participants as male particip
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Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that
15% of people have Rh- factor
This means that
52% of people have type O or Rh- factor.
This means that
a. Find the probability that a person has both type O blood and the Rh- factor.
This is
With what we have
0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
Step-by-step explanation:
Let the quotient be represented by 'Q'.
Given:
The difference of a number 'y' and 16 is
Quotient is the answer that we get on dividing two terms. Here, the first term is 40 and the second term is . So, we divide both these terms to get an expression for 'Q'.
The quotient of 40 and is given as:
Now, we need to find the quotient when . Plug in 20 for 'y' in the above expression and evaluate the quotient 'Q'. This gives,
Therefore, the quotient is 10, when the value of 'y' is 20.