Help i just need some help with thos

What is the proper structure for 3-methylpentane? draw the molecule on the canvas by choosing buttons from the tools (for bonds)

Sergio039 [100]

Below is the structure of 3-Methylpentane. The word pentane in name specifies the parent chain which ends on -ane (alkane) and pent- shows number of carbon atoms is parent chain (pent=5). The position of substituent is specified at the start i.e. 3.

5 0

3 years ago

How to draw Hess' Cycle for this question ?

NISA [10]

Answer : The standard enthalpy of formation of ethylene is, 51.8 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of $C_2H_4$ will be,

$2C(s)+2H_2(g)\rightarrow C_2H_4(g)$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$ $\Delta H_1=-1411kJ/mole$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_2=-393.7kJ/mole$

(3) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_3=-285.9kJ/mole$

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equations, we get :

(1) $2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)$ $\Delta H_1=+1411kJ/mole$

(2) $2C(s)+2O_2(g)\rightarrow 2CO_2(g)$ $\Delta H_2=2\times (-393.7kJ/mole)=-787.4kJ/mole$

(3) $2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)$ $\Delta H_3=2\times (-285.9kJ/mole)=-571.8kJ/mole$

The expression for enthalpy of formation of $C_2H_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(+1411kJ/mole)+(-787.4kJ/mole)+(-571.8kJ/mole)$

$\Delta H=51.8kJ/mole$

Therefore, the standard enthalpy of formation of ethylene is, 51.8 kJ/mole

7 0

3 years ago

HELP I WILL MARK YOU AS THE BRAINLIEST ANSWER

borishaifa [10]

Hey there! Here is the answer:

B.) decrease; increase

Here's why:

As you move from left to right across a period on the periodic table the size of an atom will decrease. As you move from top to bottom down a group on the periodic table the size of an atom will increase.

I really hope this answer helps you out! :)

8 0

3 years ago

Which of the following is a density-independent factor?

Readme [11.4K]

C.) Natural Disaster is Independent of that!

Hope this helps!

7 0

3 years ago

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Work is being done in which of these situations? All motions are at a constant velocity (including velocity = zero).

tigry1 [53]

Answer:

None of the above

Explanation:

Work is defined as the force that moves an object through a particular distance:

Workdone = force x displacement

At constant velocity, the force on a body is zero because such a body is not accelerating.

Force is a product of mass and acceleration. Acceleration occurs only when velocity changes with time. If no change in velocity, acceleration does not occur. Therefore, no force is being applied.

From all the situations given, the condition is set at constant velocity. At constant velocity, there is no acceleration. This implies that no work is done.

5 0

3 years ago

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