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finlep [7]
3 years ago
7

Which one is right i need help

Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:

C

Step-by-step explanation:

In answer C as X increases so does Y.

X increased by the value of 3.

Y also increases by the value of 3.

If this is correct may I please have brainliest? I would appreciate it a lot.

Thank you and good luck on your studies.

Zepler [3.9K]3 years ago
6 0
The answer is A.

Hope that helps!
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Find the area of the triangle.<br> 24 in.<br> 32 in.
mrs_skeptik [129]

Answer:

A = 384 inches^2

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh  where b is the length of the base and h is the height

A = 1/2 ( 32) *(24)

A = 384 inches^2

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3 years ago
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irina [24]

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Step-by-step explanation:

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3 years ago
Please help! I need it correctly please!! I can't fail this lesson.
DIA [1.3K]

Answer:

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Step-by-step explanation:

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The length and width of a rectangle are measured as 30cm and 24cm, respectively, with an error in measured of
larisa [96]

Answer:

The maximum error in the calculated area of rectangle is 5.4 cm².

Step-by-step explanation:

Given : The length and width of a rectangle are measured as 30 cm and 24 cm, respectively, with an error in measured of  at most 0.1 cm in each.

To find : Use differentials to estimate the maximum error in the calculated area of rectangle ?

Solution :

The area of the rectangle is A=l\times w

The derivative of the area is equal to the partial derivative of area w.r.t. length times the change in length plus the partial derivative of area w.r.t. width times the change in width.

i.e. dA=\frac{\partial A}{\partial L}\Delta L+\frac{\partial A}{\partial W}\Delta W

Here, \frac{\partial A}{\partial L}=30,\ \frac{\partial A}{\partial W}=24 ,\ \Delta L=0.1,\ \Delta W=0.1

Substitute the values,

dA=(30)(0.1)+(24)(0.1)

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Therefore, the maximum error in the calculated area of rectangle is 5.4 cm².

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Step-by-step explanation:

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