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Elis [28]
3 years ago
11

Can somebody help me with this question, please? I have no idea how to do this or find the answer. :/ How many ways are there to

choose a number from the set {−96, −48, −42, −36, −18, −14, −6, 14} that is divisible by either 6 or 8?
Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

28 different ways

Step-by-step explanation:

This is a combination question. Combination has to do with selection.

Total number of element in the set = 8

Number divisible by 6 or 8 are {-98, -48, -42, -36, -18, -6}

Total number divisible by 6 or 8 is 6

The number of ways we can choose 6 items from 8 is expressed as;

8C6 = 8!/(8-6)!6!

8C6 = 8!/(2)!6!

8C6 = 8*7*6!/2!6!

8C6 = 8*7/2

8C6 = 56/2

8C6 = 28 ways

Hence there are 28 different ways

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Answer:

The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

Step-by-step explanation:

<u><em>Explanation</em></u>

<em>Given       </em>\frac{14}{8} + \frac{15}{12}<em></em>

<em></em>

<em>L.C.M     8 , 12   is  24</em>

<em>          </em>

<em>        </em>\frac{14}{8} + \frac{15}{12} = \frac{14 X 3 + 15 X 2}{24}<em></em>

<em>                   = </em>\frac{42 +30}{24} = \frac{72}{24} = 3<em></em>

<u><em>Final answer</em></u><em>:-</em>

The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

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