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myrzilka [38]
2 years ago
14

D(n)=-5(1/2)^n-1 what is the 3rd term in the sequence

Mathematics
1 answer:
Studentka2010 [4]2 years ago
7 0

Answer:

-1.25

Step-by-step explanation:

Better to write this as

a(n)= -5(1/2)^(n-1)

Then the 3rd term is a(3) = -5(1/2)^(3 - 1), or  a(3) = -5(1/2)^2  = -5/4 = -1.25

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PLEASE HELP ME!!!!!! DUE TOMORROW!!!!!!!
gayaneshka [121]

Answer:

9

Step-by-step explanation:

Initial number  occurs when x = 0

so its 9(2)^0

= 9*1

= 9  answer

8 0
3 years ago
Hello people can you help me with dis two question
____ [38]

Answer

length = 11 in

width = 6in

2 in = 5m

length =

28m ÷ 5

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3 0
2 years ago
Explain whether this dilation is an enlargement or a reduction, and how you know. Triangle A B C is enlarged to triangle A prime
Vera_Pavlovna [14]

Answer:

the answer is:

The dilation is an enlargement because the image, triangle A'B'C', is larger than the pre-image, triangle ABC.

Step-by-step explanation:

I got it right on edge

5 0
2 years ago
Read 2 more answers
Will mark as brainliest (must show work)
Sever21 [200]

Answer:

46

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW  then

m < XVY = m < YVW

      2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

      2x-x = 15-7, combine like terms

           x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY =  2x+7  = 2*8 +7 = 16 +7 = 23

m < YVW =  x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

3 0
2 years ago
Solve the following equation<br> (7X3+4X2+3X+2) + (2X2+X+5)=
rjkz [21]
The way it's written it's 
Simplify the following:
7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5
Grouping like terms, 7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5 = 7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5):7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5)
4 X^2 + 2 X^2 = 6 X^2:
7 X^3 + 6 X^2 + (3 X + X) + (2 + 5)
3 X + X = 4 X:
7 X^3 + 6 X^2 + 4 X + (2 + 5)
2 + 5 = 7:Answer:  7 X^3 + 6 X^2 + 4 X + 7
5 0
3 years ago
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