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3 years ago

A spherical ball has a radius of 12 cm. The cost to cover the sphere is $0.05/cm^2. The total cost to cover the ball is:

Mathematics

1 answer:

Umnica [9.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

surface area of sphere=4πr²=4π×12²=576π

≈576×3.1416

≈1809.5616 cm²

cost to cover=1809.5616×0.05=$90.47808≈$90.48

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Please help with 11c!?

Contact [7]

Answer:

"To the nearest year, it would be about 9 years"

Step-by-step explanation:

11c)

This is compound growth problem. It goes by the formula:

$F=P(1+r)^t$

Where

F is the future amount

P is the present (initial) amount

r is the rate of growth, in decimal

t is the time in years

Given,

P = 20,000

r = 8% = 8/100 = 0.08

F = double of initial amount = 2 * 20,000 = 40,000

We need to find t:

$F=P(1+r)^t\\40,000=20,000(1+0.08)^t\\2=(1.08)^t$

To solve exponentials, we can take Natural Log (Ln) of both sides:

$2=(1.08)^t\\Ln(2)=Ln((1.08)^t)$

Using the rule shown below we can simplify and solve:

$Ln(a^b)=bLn(a)$

We can write:

$Ln(2)=Ln((1.08)^t)\\Ln(2)=tLn(1.08)\\t=\frac{Ln(2)}{Ln(1.08)}\\t=9.0064$

To the nearest year, that would be about 9 years

5 0

3 years ago

use the fact that 10^3 = 2^10 to mentally find a vaule of n for which 2^n > 10^50 & 10^n > 2^300

Rudiy27

$2^n>10^{50}=10^{3\cdot16+2}=10^2(10^3)^{16}=10^2(2^{10})^{16}=5^22^{162}$
$2^{n-162}>25$

The least power of 2 that exceeds 25 is $2^5=32$ , so we have

$2^{n-162}=2^N>25\implies N=5\implies n-162=5\implies n=167$

- - -

$10^n>2^{300}=(2^{10})^{30}=(10^3)^{30}=10^{90}$

The least integer $n$ that satisfies this inequality would clearly be $n=91$ .

6 0

3 years ago

Add: 4/100 + 2/10 = A) 6/10 B) 6/100 C) 24/100 D) 42/100

vovangra [49]

You have to find the least common variable, and that would be 10. multiply 2/10 by 10 to get 20/100. 4/100+20/100=24/100. it's C

3 0

4 years ago

Read 2 more answers

I need help with this question

Jet001 [13]

Answer:

286 Degrees