Why is a negative times a negative always a positive?

Mathematics

1 answer:

kondaur [170]3 years ago

3 0

Answer: A negative times a negative is always positive because the two negative signs are canceled out.

Step-by-step explanation:

If you seek a more in-depth explanation, Khan Academy actually has a video available on this topic!

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Find the unknown length plz

tigry1 [53]

I
tan(32)x21=13mm
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7.32/cos(66)=17.9cm
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tan(34)x26.8=18m
i
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3 years ago

F the point T is between the points B and N, then which of the following is true?

valentina_108 [34]

Assuming T, B and N are all on the same line, then we can say

BT + TN = BN

which is the segment addition postulate.

Subtract TN from both sides to get
BT + TN = BN
BT + TN - TN = BN - TN
BT = BN - TN
BN - TN = BT

Which is what choice C is saying. Therefore the answer is choice C.

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4 years ago

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3(3p +5) -6p + 3p(5-1)

lesya692 [45]

Answer:

15p+15

Step-by-step explanation:

3(3p+5)-6p+3p(5-1)

9p+15-6p+3p(4)

9p-6p+15+12p

3p+12p+15

15p+15

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3 years ago

If a=i+7j+k and b=i+11j+k, find a unit vector with positive first coordinate orthogonal to both a and

Scilla [17]

Take the cross product, then normalize the result.

$\mathbf a\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\1&7&1\\1&11&1\end{vmatrix}=-4\,\mathbf i+4\,\mathbf k$

This has norm

$\|\mathbf a\times\mathbf b\|=\sqrt{(-4)^2+4^2}=4\sqrt2$

and so a unit vector orthogonal to both given vectors is

$\dfrac{\mathbf a\times\mathbf b}{\|\mathbf a\times\mathbf b\|}=-\dfrac1{\sqrt2}\,\mathbf i+\dfrac1{\sqrt2}\,\mathbf k$

An equally correct answer would be the negative of this vector, since $\mathbf b\times\mathbf a=-\mathbf a\times\mathbf b$ .

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3 years ago

Sebastian and Mia want to buy a home valued at $250,000. The property tax for this location is 1%. Based on the current value of

denis-greek [22]

1% of $250,000 is $2,500

Your answer is C

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4 years ago

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