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german
3 years ago
15

1. What is the value of this expression when c = 4? 4C+ 3c- 2c

Mathematics
1 answer:
vampirchik [111]3 years ago
8 0

Answer:

20

Step-by-step explanation:

4(4)+3(4)-2(4)=20

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Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
4 years ago
What is the range of y = sin θ ?
seraphim [82]
For the answer to the question above, For θ the range is between -infinity and infinity, 
<span>While y falls in the range from -1 to 1.
because </span><span>y is an element of [-1, 1]</span>
I hope my answer helped you in your problem. Have a nice day!
8 0
3 years ago
What is the value of x<br>|5x + 6| + 6 = x​
zimovet [89]

Answer:

Step-by-step explanation:

absolute(5x + 6) = x

There are 2 solutions to this

Solution 1

5x + 6 = x                    Subtract 5x from both sides.

5x - 5x + 6 = x - 5x

6 = - 4x                       Divide by - 4

6/ - 4  = -4x / -4

x = - 1.5

Solution 2

5x + 6 = - x

6 = -x - 5x

6 = - 6x

x = 6/-6

x = - 1

Here is a graph which shows the solutions.

3 0
3 years ago
Consolidated Power, a large electric power utility, has just built a modern nuclear power plant. This plant discharges waste wat
Gemiola [76]

Answer:

We conclude that the plant should shut down.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 60

Sample mean, \bar{x} = 61.498

Sample size, n = 100

Alpha, α = 0.05

Population standard deviation, σ = 6

a) First, we design the null and the alternate hypothesis  such that the power plant will be shut down when the null hypothesis is rejected.

H_{0}: \mu \leq 60\\H_A: \mu > 60

We use One-tailed(right) z test to perform this hypothesis.

b) Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{61.498 - 60}{\frac{6}{\sqrt{100}} } = 2.49

Now, z_{critical} \text{ at 0.05 level of significance } = 1.64

Since,  

z_{stat} > z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, the temperature of waste water discharged is greater than 60°F. We conclude that the power plant will shut down.

Calculating the p-value from the z-table:

P-value = 0.0063

Since,

P-value < Significance level

We reject the null hypothesis and accept the alternate hypothesis. Thus, the temperature of waste water discharged is greater than 60°F. We conclude that the power plant will shut down.

7 0
4 years ago
Find the inverse of the given function
xenn [34]

For this case, we must find the inverse of the following function:

f (x) = \frac {5x + 1} {- x + 7}\\x\neq 7

To find the inverse we follow the steps below:

y = \frac {5x + 1} {- x + 7}

We rewrite the denominator:

y = \frac {5x + 1} {- (x-7)}\\y = - \frac {5x + 1} {(x-7)}

We exchange variables:

x = - \frac{5y + 1} {(y-7)}

We solve for y:

We multiply on both sides of the equation by (y-7)

x (y-7) = - 5y-1\\xy-7x = -5y-1

We subtract xy on both sides of the equation:

-7x = -5y-1-xy

We add 1 to both sides:

-7x + 1 = -5y-xy

We factor for y:

-7x + 1 = y (-5-x)

We divide both sides by (-5-x):

y = \frac {-7x + 1} {- 5-x}

So, we have:

f ^ {- 1} (x) = \frac {-7x + 1} {- 5-x}

Answer:

f ^ {- 1} (x) = \frac {-7x + 1} {- 5-x}

x\neq -5

3 0
4 years ago
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