There are many examples to pick from, but one example is this:
The set of rational numbers (aka any fraction of two integers) is closed under the operation of division. Divide any two rational numbers and we get some other rational number.
However, the set of integers is not closed under division. If we divided 10 over 3, then we get 10/3 = 3.333 approximately which isn't an integer. So just because the set of integers is a subset of the rationals, it doesn't mean that the idea of closure follows suit from superset to subset.
Side note: The term "superset" is basically the reverse of a subset. If A is a subset of B, then B is a superset of A.
If m∠F=40° then m∠D=40°
m∠F, m∠D and m∠G have to be 180° together in order to form a triangle
So m∠G = 180° - 2×40° = 100°
One line is cutting m∠G in half and we get m∠EGF and m∠EGD
We want to know how much m∠EGF is so...
m∠EGF=100°÷2=50°
Now we have m∠F which we can name m∠EFG and we have m∠EGF
Together with m∠FEG they form a triangle so that means together they have the value of 180°
m∠FEG=180°-40°-50°=90°
And because you have parralel lines m∠FEG=m∠CBE
And m∠ABE=180°-m∠CBE=90°
That is if I understand this correctly
Answer:
Now, you might immediately recognize that this is a proportional relationship. And remember, in order for it to be a proportional relationship, the ratio between the two variables is always constant. So, for example, if I look at y over x here, we see that y over x, here it's four over one, which is just four.
Step-by-step explanation:
Answer:
-16/45
Step-by-step explanation:
(-8 x 2) / (9 x 5)
-16/45
Answer:
Option C.
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form or
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
so
Find the value of the constant k
For the point (-8,-6)
For the point (12,9)
<u><em>Note</em></u> A single point was required to find the constant k (because the line passes through the origin)
The equation is equal to