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dedylja [7]
2 years ago
7

Math-geometry 9th grade I rlly need help with this finding x

Mathematics
1 answer:
Naya [18.7K]2 years ago
5 0

Answer:

1)x=11

2)x=9

Step-by-step explanation:

In the picture

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A salesperson is paid an 8.25% commission on sales when the invoice is
son4ous [18]

Answer:

<em>The salesperson's commission for this month is $3,803</em>

Step-by-step explanation:

<u>Percentages</u>

Let's call x to the sales volume, not including commission.

The salesperson is paid an 8.25% commission on sales, thus the total invoice is x + 8.25%x = x + 0.0825x = 1.0825x

We are given this total invoice, thus:

1.0825x = $49,900

Dividing by 1.0825:

x = $46,097

The salesperson's commission is

0.0825*$46,097=$3,803

The salesperson's commission for this month is $3,803

7 0
2 years ago
4/5 y = 8 , how do we solve pls help fast its urgent, I will mark u brainliest
Butoxors [25]

Answer:

y = 10

Step-by-step explanation:

4/5 y = 8

4/5 y * 5/4 = 8 * 5/4           multiply by reciprocal

y = 10

4 0
3 years ago
Read 2 more answers
1. cot x sec4x = cot x + 2 tan x + tan3x
Mars2501 [29]
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
    cot(x)sec⁴(x)            cot(x)sec⁴(x)
                   0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
                   0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
                   0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
                   0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
                   0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
                   0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
                   0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
                   0 = cos⁴(x)(1 + tan²(x))²
                   0 = cos⁴(x)        or         0 = (1 + tan²(x))²
                ⁴√0 = ⁴√cos⁴(x)      or      √0 = (√1 + tan²(x))²
                   0 = cos(x)         or         0 = 1 + tan²(x)
         cos⁻¹(0) = cos⁻¹(cos(x))    or   -1 = tan²(x)
                 90 = x           or            √-1 = √tan²(x)
                                                         i = tan(x)
                                                      (No Solution)

2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
              sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
   sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
                               sin²(x) - cos²(x) = sin²(x) - cos²(x)
                                         + cos²(x)              + cos²(x)
                                             sin²(x) = sin²(x)
                                           - sin²(x)  - sin²(x)
                                                     0 = 0

3. 1 + sec²(x)sin²(x) = sec²(x)
           sec²(x)             sec²(x)
      cos²(x) + sin²(x) = 1
                    cos²(x) = 1 - sin²(x)
                  √cos²(x) = √(1 - sin²(x))
                     cos(x) = √(1 - sin²(x))
               cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
                                 x = 0

4. -tan²(x) + sec²(x) = 1
               -1               -1
      tan²(x) - sec²(x) = -1
                    tan²(x) = -1 + sec²
                  √tan²(x) = √(-1 + sec²(x))
                     tan(x) = √(-1 + sec²(x))
            tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
                             x = 0
5 0
3 years ago
Byron earns $11.00 per hour. How many hours will Byron have to work to earn $143.00?
kirza4 [7]
Byron would have to work 13 hours to earn $143.00
8 0
3 years ago
Read 2 more answers
HELP PLS!!! make sure to submit a pic of the graph!<br> Graph the piecewise function.
Ad libitum [116K]

Answer:

I cant graph on here

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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