Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90



has a pvalue of 0.9649
X = 82



has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
Answer:
<u>a</u>
Step-by-step explanation:
Given :
⇒ P (Sumit) = 1/2
⇒ P (Sujan) = 1/3
⇒ P (Rakesh) = 1/a
⇒ P (total) = 3/4
============================================================
Solving :
⇒ 1/2 × 1/3 × 1/a = 3/4
⇒ 1/6 × 1/a = 3/4
⇒ 2/12 × 1/a = 9/12
⇒ a = <u>9/2</u>
Answer:
44
Step-by-step explanation:
there you goooooo oooooooooooooooooo
To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.