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Dominik [7]
3 years ago
6

Help pls someone pls help me

Mathematics
1 answer:
larisa [96]3 years ago
3 0

Answer:

hi

Step-by-step explanation:

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Solve for x : 2x−3 = 5
neonofarm [45]

Answer:

x=4

Step-by-step explanation:

2x-3=5

Add 3 to both sides

2x=8

divide both sides by 2

x=4

3 0
4 years ago
Read 2 more answers
Fill in the blank: _ _ _ _ _ _ × _ _= 11111111
galina1969 [7]
5555555.5 × 2 = 11111111
Hope it helps!
5 0
4 years ago
A sample of 100 college students is selected from all students registered at a certain college, and it turns out that 38 of them
nasty-shy [4]

Answer:

a.   False

b. True

Step-by-step explanation:

Given that:

The sample size of the college student n = 100

The population of student that participated p = 38

We are to identify from the following statement if it is true or false.

From part a;

It is false since the random samples not indicate the population perfectly. As such we can't conclude that the proportion of students at this college who participate in intramural sports is 0.38.

The statement in part b is true because the sampling variation, random samples also do not indicate the population perfectly but it is close to be 0.38. Thus, it is suitable to conclude that the proportion of students at this college who participate in intramural sports is likely to be close to 0.38, but not equal to 0.38.

7 0
3 years ago
10. Jessica had dance class for 3 hours last night, Tiffany had dance class for of time that Jessica had dance class. How long d
Stolb23 [73]

Answer:

i think theres a typo somewhere

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method
hram777 [196]

Answer:

<h2>S = 9/20</h2><h2>J = 113/50</h2>

Step-by-step explanation:

5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\  S = 9/20\\

Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50

4 0
4 years ago
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