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Gwar [14]
3 years ago
5

Your parents are redecorating the dining room and want to place two rectangular pictures, each measuring 25 inches

Mathematics
1 answer:
Nostrana [21]3 years ago
5 0

Answer:

There isnt a question in that

Step-by-step explanation:

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Which ordered pair is the solution to the system of equations?<br><br> 2x-5y=-5<br> x+2y=11
oee [108]
2x-5y= -5
-2/*x+2y=11

2x-5y= -5
-2x-4y= -22
+------------------
-9y=-27
y=3

x+2y=11
x+2*3=11
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7 0
4 years ago
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Please help me I'm begging you!!!​
anygoal [31]

Answer:

Your correct answer is E!

Step-by-step explanation:

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3 years ago
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What is the recursive formula for this arithmetic sequence 6, -24, 96, -384
Artemon [7]

Answer:

Option A. a_{1} =6  a_{n}= a_{n-1}(-4)

Step-by-step explanation:

The given sequence in the question is 6,-24,96,-384.......n

and we have to give the recursive formula for this arithmetic sequence.

We can re write the sequence to make it more simpler

6,6(-4),(-24)(-4),(96)(-4).......n terms

Now we can say a_{1} = 6

and a_{n}= a_{n-1}(-4)

Therefore the recursive formula of the sequence is a_{1} = 6

a_{n}= a_{n-1}(-4)

7 0
3 years ago
Find the angles in this quadilateral
ch4aika [34]

Answer:

Therefore a= 90°,b=54°, x=54°, y= 162°

Step-by-step explanation:

a=90°

a:b=5:3

5+3= 8

5/8 x A = 90

A is the sum of the angles of a and b divided in the ratio 5:3

5A/8 = 90

cross multiply

5A= 90 X8 = 720

5A=720

A= 720/5= 144°

b= 3/8 x 144 = 3x144/8 = 432/8 = 54

a= 90

b= 54

x:y is in the ratio of 1:3

the Sum of angles in a Quadrilateral is 360°

if the sum of a and b is 144°

then the reamining angles is 360-144= 216°

then x:y=1:3

1+3=4

x= 1/4 x 216= 54°

y= 3/4 x 216= 162°

Therefore a= 90°,b=54°, x=54°, y= 162°

we can see that b = x = 54°

7 0
3 years ago
A soccer ball is kicked from the ground in an arc defined by the function, h(x) = -2x 2 + 8x. At what point does the ball hit th
Makovka662 [10]
Check the picture below.  That's about what a parabola for an "initial velocity" case would look like.

anyhow, it hits the ground at two points, when it began, and when it came back down, and that happens when y = 0.

\bf h(x)=-2x^2+8x\implies \stackrel{h(x)}{0}=-2x^2+8x\implies 0=-2x(x-4)\\\\&#10;-------------------------------\\\\&#10;0=-2x\implies 0=x\qquad \impliedby \textit{when it began}\\\\&#10;-------------------------------\\\\&#10;0=x-4\implies \boxed{4=x}\qquad \impliedby \textit{when it came back down}

4 0
4 years ago
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