Answer:
(sin x)^2*(sec x) is positive in QII
Step-by-step explanation:
(sin x)^2 is always 0 or positive. Here x lies in QII.
sec x is positive when the adjacent side is positive and negative when the adjacent side is negative. In QII the adjacent side is positive.
In summary, (sin x)^2*(sec x) is positive in QII
Your solution My solution
8p (>/=) -7 8p >/= -7
8p/8 (=) -7/8 <span>8p/8 </span>>/= -7/8
<span>p (=) -7/8 </span><span>p </span>>/= <span> -7/8</span>
The last two equation only has the equal "=" sign. The greater than ">" sign was removed.
Greater than ">" sign should not be removed because the expression is an inequality.
Inequality expressions deal with numerous numbers that can make the inequality true.
Putting only an equal sign will limit the number option into 1. It will only make half of the inequality true. P = -7/8 but it is not > -7/8.
34, because it says 34 options for pizzas with different toppings
Do you have a picture of the polygon?
What is the rest of the question or problem?