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3 years ago

What is the sum of angles JMK and KML?

Mathematics

1 answer:

Anton [14]3 years ago

5 0

Answer:

the sum of angles JMK and KML is

( 160 + 90)°

= 252°

Hope it helps :)

Step-by-step explanation:

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Please help me Answer the encircled numbers only

MrRissso [65]

I hope this helps you

3 0

3 years ago

Factorise 25x+15 mate

Ivanshal [37]

Answer:

5(5x+3)

Step-by-step explanation:

25x=5*5x

15=5*3

5*5x+5*3

Factor out the Common 5

5(5x+3)

6 0

3 years ago

Which formula would be used to find the measure of angle 1?

Stels [109]

What’s angle 1? U need to post a pic

7 0

3 years ago

Solve for x in the equation.

labwork [276]

Answer:

The solution is $\displaystyle x=1\pm \sqrt{47}$ . Fourth option

Explanation:

Solve for x:

$2x^2+3x-7=x^2+5x+39$

Move all the terms from the right to the left side of the equation, a zero in the right side:

$2x^2+3x-7-x^2-5x-39=0$

Join all like terms:

$x^2-2x-46=0$

The general form of the quadratic equation is:

$ax^2+bx+c=0$

Solve the quadratic equation by using the formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

In our equation: a=1, b=-2, c=-46

Substituting into the formula:

$\displaystyle x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-46)}}{2(1)}$

$\displaystyle x=\frac{2\pm \sqrt{4+184}}{2}$

$\displaystyle x=\frac{2\pm \sqrt{188}}{2}$

Since 188=4*47

$\displaystyle x=\frac{2\pm \sqrt{4*47}}{2}$

Take the square root of 4:

$\displaystyle x=\frac{2\pm 2\sqrt{47}}{2}$

Divide by 2:

$\displaystyle x=1\pm \sqrt{47}$

First option: Incorrect. The answer does not match

Second option: Incorrect. The answer does not match

Third option: Incorrect. The answer does not match

Fourth option: Correct. The answer matches exactly this option

8 0

3 years ago

The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi

kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0

3 years ago