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kirza4 [7]
3 years ago
5

Plzzz help me with this math im so confused!!

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0

Answer:

I have made it in above picture

kotykmax [81]3 years ago
3 0

Answer:

2 A.)

1) 3-4x+8x^2-6+2x-5x^2

2) 8x^2-5x^2-4x+2x+3-6

3) 3x^2-2x-3

B.) 3x-5-7x^2+2+6x^2+5x

Step-by-step explanation:

please mark brainiest

please give 5 stars

thank you

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I didn’t do this but my friend needs help so help
yuradex [85]

Answer:

1. X = 14

2.X =13

Step-by-step explanation:

The angles are 90 degrees. I did math to check if the x values are correct and they are.

8 0
3 years ago
What is the GCF of 24,44,52
statuscvo [17]
The greatest common factor (GCF) of 24, 44, and 52 is: 4

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 44: 1, 2, 4, 11, 22
Factors of 52: 1, 2, 4, 13

The common factors between them are 1, 2, and 4, but 4 is the greatest, making it the GCF. 
4 0
3 years ago
Wendy is helping her mom put candy in 217 giftbagd. Each bag has 7 pieces of candy. She already put 58 pieces of candy in the ba
Ganezh [65]

Answer:

406 pieces. If you multiply 58 times 7 you get 406. 406 divided by 58 is 7.

4 0
2 years ago
7. Sapna travelled 48 km to meet her parents. She travelled the first 18 km by car and the remaining distance by train. Find the
Anton [14]

The fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

We know that fraction is an expression in mathematics used to denote the division of two whole numbers.

Given that the total distance = 48 km.

The distance Sapna traveled by car = 18 km.

So, the fraction is = distance traveled by car/total distance = 18/48 = 3/8

The distance Sapna traveled by train = 48 - 18 km = 30 km.

So, the fraction is = distance traveled by train/total distance = 30/48 = 5/8

Therefore the fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

Know more about fractions here -

brainly.com/question/10354322

#SPJ10

6 0
2 years ago
Kevin is observing the population of the fish he put into a pond. He built a pond and populated it with 500 fish. The population
laila [671]

Here we will use exponential form, which is

y = y_{0} e^{kt}

Initial value, y0 = 500

Double of 500 = 1000

1000 = 500e^{k*1}

2 = e^k

k= ln (2)

Required equation is

y=500e^{x ln2} \\ y= 500 (2)^x

6 0
3 years ago
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