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joja [24]
3 years ago
5

PLEASE HELP ME!! 99 POINTS!!!!!!

Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

=> 51b - 24

=> 51(4) - 24

=> 204 - 24

=> 180

Llana [10]3 years ago
3 0

Answer:

<u><em>A. 87b-179+957/87</em></u>

<u><em>D. 51b-24</em></u>

Step-by-step explanation:

A. 87(4)-179+957/87

348-179+957/87

348-179+11

169+11

<u><em>180</em></u>

B. 33b12

33(4)12

553648128

C. b2+120

(4)2+120

8+120

128

D. 51b-24

51(4)-24

204-24

<u><em>180</em></u>

E. 11b+187-2756/13

11(4)+187-2756/13

44+187-2756/13

44+187-212

231-212

19

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A sample of 20 pages was taken from a Yellow Pages directory. On each page, the mean area devoted to display ads was measured in
Snezhnost [94]

The 95 percent confidence interval for the mean is (266.76,426.24).

A confidence interval is how much uncertainty there is with any particular statistic. Confidence intervals are often used with a margin of error. It tells you how confident you can be that the results from a poll or survey reflect what you would expect to find if it were possible to survey the entire population. Confidence intervals are intrinsically connected to confidence levels.

The formula of Confidence Interval =  Mean ±   t\frac{Standard Deviation}{\sqrt{number of observations} }

where t is a constant

Given:

Mean = 346.5

Standard Deviation = 170.378

t-critical value for 95% Confidence interval with degrees of freedom(df)=n-1= 19 is 2.093

∴ Substituting values in formula we get

E = 2.093 X170.378/\sqrt{20} = 2.0931.96 x 38.0976=79.74

95% Confidence interval : (346.5-79.74,346.5+79.74)

95% Confidence interval : (266.76,426.24)

Learn more about confidence intervals here :

brainly.com/question/24131141

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4 0
2 years ago
A blackboard has an area of 28 and a perimeter of 22 ft. What are the dimensions of the board?
Alex787 [66]

Answer:

the ancer is c

Step-by-step explanation:

Answer:

Option (c) is correct.

Dimension of board is 4 ft by 7 ft.

Step-by-step explanation:

Given : A blackboard has an area of 28 feet squared and a perimeter of 22 ft.

We have to find the dimension of blackboard and choose the correct option from given options.

Since blackboard is in shape of rectangle thus,

Area of blackboard is 28 feet²

That is, Area of rectangle =  28 feet²

We know Area of rectangle = length × Breadth

substitute, we get,

28 = length × Breadth ......(1)

Also, Perimeter of blackboard is 22 feet.

That is, Perimeter of rectangle =  22 feet

We know, Perimeter of rectangle = 2 (length + Breadth)

substitute, we get,

22 = 2 (length + Breadth)  

11 = (length + breadth)   ........(2)

Let length be l and breadth be b

Solving (1) and (2) ,

from (2)

b = 11 - l  ..(3)

put (3)  in (1) , we get,

28 = L (11 - L)

Multiply, we get,

Solving above quadratic equation using middle term split method, we get,

Solving, e get,

Using zero product property, we get,

 and

We get ,

 and

Thus, length can be 4ft or 7 ft

Substitute, L in (3) , we get,

b = 11 - 4 = 7 ft

b = 11 - 7 = 4 ft

Thus, Dimension of board is 4 ft by 7 ft.

Option (c) is correct. hope it helped <3

5 0
4 years ago
Read 2 more answers
1. A line segment has endpoints of Y(2,-3) and Z(-6,-1).
Orlov [11]

The answers will be :

a. The length of the line segment will be equal to 8.24 units.

b. The midpoint of the line segment will be ( -2 , -2 ).

c. The equation of line passing through points Y and Z will be 4y + x - 10 = 0

What is slope of a line segment ?

The ratio of the difference in y-coordinates over the equivalent x-coordinates between two different locations on a line.

It is given that a line segment has endpoints of Y(2,-3) and Z(-6,-1).

Let's solve the given parts based on the above data.

a.

The length of the line segment will be given by :

YZ = \sqrt({x_{2} - x_{1})^2 + (y_{2}- y_{1})^2}

YZ = √ [( -6 -(2)]^2 + [ -1 - (-3)]^2}

YZ = √ (-8)² + 2²)

YZ = √68

YZ = 8.24 units

b.

The midpoint (say M) of the line segment will be given by :

M = ( \frac{x_{1} + x_{2} }{2} , \frac{y_{1} + y_{2} }{2})

M = [(2-6)/2 , (-3-1)/2]

M = ( -2 , -2 )

c.

And the equation of line passing through points Y and Z will be :

y_{2} - y_{1} = m ( x_{2} - x_{1} )

Let's calculate value of slope (m) firstly which will be :

m =(y_{2} - y_{1}) / ( x_{2} - x_{1} )

m = ( -1 + 3 ) / (-6 - 2)

m = 2 / -8

m = -1 / 4

or

m = -0.25

Using the value of slope (m) : we get the equation of line as :

y - y_{1} = - 0.25 ( x - x_{1} )

or

(y + 3) = - 0.25 ( x - 2)

y + 3 = -0.25 x + 0.50

or

y + 0.25 x - 2.5 = 0

If we multiply by 4 throughout the equation ; then the equation of line can also be written as :

4y + x - 10 = 0

Therefore the answers will be :

a. The length of the line segment will be equal to 8.24 units.

b. The midpoint of the line segment will be ( -2 , -2 ).

c. The equation of line passing through points Y and Z will be 4y + x - 10 = 0

Learn more about line segment here ;

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5 0
1 year ago
What is syntax error from line 1 column 53 to line 1 column 60. unexpected '0'. expressed as the quotient of two integers in sim
Anon25 [30]
Believe it would be 7. not to sure.
4 0
4 years ago
According to the manufacturer of the candy Skittles, 20% of the candy produced are red. If we take a random sample of 100 bags o
WITCHER [35]

Answer:

0.15651

Step-by-step explanation:

This can be approximated using a Poisson distribution formula.

The Poisson distribution formula is given by

P(X = x) = (e^-λ)(λˣ)/x!

P(X ≤ x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to x)

where λ = mean of distribution = 20 red bags of skittles (20% of 100 bags of skittles means 20 red bags of skittles)

x = variable whose probability is required = less than 16 red bags of skittles

P(X < x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to (x-1))

P(X < 16) = Σ (e^-λ)(λˣ)/x! (Summation From x=0 to x=15)

P(X < 16) = P(X=0) + P(X=1) + P(X=2) +......+ P(X=15)

Solving this,

P(X < 16) = 0.15651

4 0
3 years ago
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