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MissTica
3 years ago
10

​ △ABC∼△EFG ​. Given m∠C=52° and m∠E=61° , what is m∠B ?

Mathematics
2 answers:
Dvinal [7]3 years ago
8 0

In this question , it is given that

△ABC∼△EFG ​.

Given m∠C=52° and m∠E=61°

Since the triangles are similar, so we have

m∠C=m∠G=52°

m∠A=m∠E=61°

m∠B=m∠F=x

And sum of measurements of angles of a triangle is 180 degree, that is

m \angle A + m \angle B + \angle C = 180

52+61+x =180
\\
113 +x = 180
\\
113+x-113 = 180-113
\\
x = 67

So the measurement of angle B is 67 degree.


Alexandra [31]3 years ago
6 0
Did you you get the answer to this one?

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Step-by-step explanation:

From the question we are told that

   The function is  f(x, y) =  9sin(xy) \ \ \

    The point considered is  (0,8 )

Generally the maximum rate of change of f at the given point and the direction is mathematically represented as

            \Delta f(x,y) =  [\frac{\delta  f(x,y)}{\delta x } i + \frac{\delta  f(x,y)}{\delta y } j  ]

             \Delta f(x,y) =  [\frac{\delta  (9sin(xy))}{\delta x} i  + \frac{\delta  (9sin(xy))}{\delta y} i   ]

            \Delta f(x,y) = [9y cos (x,y) i +  9xcos (x,y) j]

At  (0,8 )

            \Delta  f (0,8) =  [9(8) cos(0* 8)i  + 9(8) sin(0* 8)j  ]

            \Delta  f (0,8) = 72 i

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