Question

If CD = 7√3, find AE I give you 25, PLSS HELPPP

Answer 1

Answer:

AE = 22.86

Step-by-step explanation:

In triangle CDE

cos 30° = CD/CE

$\frac{\sqrt 3}{2} = \frac {7\sqrt 3}{CE}$

$CE= {7\sqrt 3}\times \frac{2}{\sqrt 3}$

$CE= 14$

In triangle BCE

sin 45° = CE/BE

$\frac{1}{\sqrt 2}= \frac{14}{BE}$

$BE= 14\sqrt 2$

In triangle ABE

sin 60° = BE/AE

$\frac{\sqrt 3}{2}= \frac{14\sqrt 2}{AE}$

$AE= 14\sqrt 2\times\frac{2}{\sqrt 3}$

$AE= \frac{28\sqrt 2}{\sqrt 3}$

$AE= \frac{28\sqrt 6}{ 3}$

$AE= \frac{68.5857128}{ 3}$

AE = 22.8619043

AE = 22.86