We have the isosceles triangle were y + 12 = 3x - 5,
and the equilateral triangle. Therefore 3x - 5 = 5y - 4.
From the first equation and the second equation we have:
y + 12 = 5y - 4 <em>subtract 12 from both sides</em>
y = 5y - 16 <em>subtract 5y from both sides</em>
-4y = -16 <em>divide both sides by (-4)</em>
<h3>y = 4</h3>
Substitute the value of y to the first equation:
4 + 12 = 3x - 5
16 = 3x - 5 <em>add 5 to both sides</em>
21 = 3x <em>divide both sides by 3</em>
<h3>x = 7</h3>
<h3>Answer: x = 7 and y = 4</h3>
Answer:
2+2+1+1+1+1+1=
9
Step-by-step explanation:
Have a great day
#Nova
The answer would probably be B
Answer:
-2 - 16 = -18
Step-by-step explanation:
-y+4c
You take the values for c and y and substitute them in the original equation.
It would then look like:
-(2) + 4(-4)
Solving that would be -2 -16 = -18
Answer:
A. (1, 0)
Reason:
When the first equation is graphed: y <u><</u> x + 1, the left side of the line is shaded and when the second equation is graphed: y <u><</u> x^2 -3x, the bottom is shaded.
The green section does not contain solutions. So D is automatically out.
The red section does not contain solutions as well. So C is automatically out.
For choice B, the point goes out of the shaded blue section, so that's out also.
As for choice A its in the blue shaded section, which makes that answer correct.
(when the two equations are within each other and combine a color, then whatever points is within the shaded part is the right answer)