Equation of the parabola: y = ax^2 + bx + c. Find a, b, and c.
x of axis of symmetry:
x
=
−
b
2
a
=
3
-> b = -6a
Writing that the graph passing at point (1, 0) and point (4, -3):
(1) 0 = a + b + c -> c = - a - b = - a + 6a = 5a
(2) -3 = 16a + 4b + c --> -3 = 16a - 24a + 5a = -3a --> a = 1
b = -6a = -6; and c = 5a = 5
y
=
x
2
−
6
x
+
5
Check with x = 1: -> y = 1 - 6 + 5 = 0. OK
Answer:
3/20 is the answer.......
I worked out the problem hope it helps
First, you need to substitute y for 2/3:
2/3 • 6
Next, change 6 into a fraction and multiply straight across:
2/3 • 6/1
12/3
Finally, simplify it to its simplest form:
4
Your answer should be 4.
Hopefully that helped!
The answer would be 2 2/3.
