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Semmy [17]
3 years ago
8

Please help !!! Due instant

Mathematics
1 answer:
Vinvika [58]3 years ago
4 0
I believe the range is 25.
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2-(-8) please answer
zepelin [54]

Answer:

10

Step-by-step explanation:

- and a - equal postive and 8 plus 2 is 10

6 0
3 years ago
Read 2 more answers
Which ordered pair is a solution of this equation y = 80 – 8x?​
Lisa [10]

Answer:

y = -8x + 80 This is the way I found the answer

4 0
3 years ago
Use lagrange multipliers to find the point on the plane x − 2y + 3z = 6 that is closest to the point (0, 2, 5).
horsena [70]
Lagrangian:

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-5)^2+\lambda(x-2y+3z-6)

where the function we want to minimize is actually \sqrt{x^2+(y-2)^2+(z-5)^2}, but it's easy to see that \sqrt{f(\mathbf x)} and f(\mathbf x) have critical points at the same vector \mathbf x.

Derivatives of the Lagrangian set equal to zero:

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-5)+3\lambda=0\implies z=5-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0

Substituting the first three equations into the fourth gives

-\dfrac\lambda2-2(2+\lambda)+3\left(5-\dfrac{3\lambda}2\right)=6
11-7\lambda=6\implies \lambda=\dfrac57

Solving for x,y,z, we get a single critical point at \left(-\dfrac5{14},\dfrac{19}7,\dfrac{55}{14}\right), which in turn gives the least distance between the plane and (0, 2, 5) of \dfrac5{\sqrt{14}}.
7 0
3 years ago
Veronica is framing a rectangular picture. She uses 72 inches of framing. The picture is 20 inches long. What is the width of th
Marina CMI [18]

Answer:

3.6

Step-by-step explanation:

Using the area of rectangle formula L*W= A

we can plug in our known values

20*w=72

then we can divide 20 on both sides giving us 3.6 inches for width.

4 0
3 years ago
Carson claims that the opposite of any integer X is always a negative number is he correct explain why or why not
viktelen [127]
I would say he is incorrect because integers are both negative and positive 
8 0
3 years ago
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