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amm1812
4 years ago
14

Can someone help me with this. Don’t mine the words on the bottom

Mathematics
1 answer:
svlad2 [7]4 years ago
7 0
Use the app math //// way
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Which shows two expressions that are equivalent to (Negative 7) (Negative 15) (Negative 5)?
Zigmanuir [339]

Answer:

negative 8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Use square roots to solve the<br>equation x2 = -121 over the<br>complex numbers.​
balandron [24]

Answer:

x = ±11i

Step-by-step explanation:

x^2 = -121

Take the square root of each side

sqrt(x^2) = sqrt(-121)

sqrt(x^2) = sqrt (-1) *sqrt(121)

We know that the sqrt(-1) is i

x = i ( ±11)

x = ±11i

5 0
4 years ago
Plz help with this question!!!! ill give brainliest to best question :)
Doss [256]
No, it's not random. You chose to poll a specific group, which shows bias towards that particular group, therefor it is not random.


Hope this helps. Best of luck to you!
8 0
3 years ago
Read 2 more answers
the sum of two number is 20 and their difference is 4. Find the ratio of greater inequality of the number.
OLga [1]
Hello,
If the numbers are a and b and (a>=b)
Are-you asking a/b ?
If yes,
a+b=20
a-b=4
==>2a=24
==>a=12 and b=20-12=8

a/b=12/8=3/2

7 0
3 years ago
A bulb can either be on or off. A board contains connected to a randomization circuit that lights up a random sequence every tim
kari74 [83]

The question is incomplete. The complete question is :

A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence every time it is turned on. What is the probability that all the lights will switch on ?

Solution :

It is given that :

There is board connected to = 20 bulbs

And one can either be put ON or put OFF.

Therefore the chance that a bulb is ON = $\frac{1}{2}$

It is given that every time a bulb turns ON, the board lights up in a random sequence.

Therefore, the probability of all the lights to be switched ON is given by :

$=\left(\frac{1}{2}\right)^{20}$

$=\frac{(1)^{20}}{(2)^{20}}$

$=\frac{1}{1048576}$

7 0
3 years ago
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