Answer:
negative 8
Step-by-step explanation:
Answer:
x = ±11i
Step-by-step explanation:
x^2 = -121
Take the square root of each side
sqrt(x^2) = sqrt(-121)
sqrt(x^2) = sqrt (-1) *sqrt(121)
We know that the sqrt(-1) is i
x = i ( ±11)
x = ±11i
No, it's not random. You chose to poll a specific group, which shows bias towards that particular group, therefor it is not random.
Hope this helps. Best of luck to you!
Hello,
If the numbers are a and b and (a>=b)
Are-you asking a/b ?
If yes,
a+b=20
a-b=4
==>2a=24
==>a=12 and b=20-12=8
a/b=12/8=3/2
The question is incomplete. The complete question is :
A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence every time it is turned on. What is the probability that all the lights will switch on ?
Solution :
It is given that :
There is board connected to = 20 bulbs
And one can either be put ON or put OFF.
Therefore the chance that a bulb is ON = 
It is given that every time a bulb turns ON, the board lights up in a random sequence.
Therefore, the probability of all the lights to be switched ON is given by :

