Question

When a process is in control, it results in there being, on average, 16 defects per unit of output. c-chart limits of 8 and 24 would lead to a

Answer 1

Answer:

4.56%

Explanation:

From the given information:

In a c-chart limit

UCL = $\bar c+ z \times \sqrt{\bar c }$

where;

$\bar c = 16$

UCL = 24

Then:

$24 = 16 + z \times \sqrt{24}$

$24 -1 6 = z \times \sqrt{24}$

$8 = z \times 4.89$

$z = \dfrac{8}{4.89}$

z $\simeq$ 2.0

At z = 2.0, the value represents the probability of 95.44% of not making a Type 1 error.

This implies that the probability of making a Type 1 error = 1 - 95.44%

= 4.56%