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3 years ago

6-2x=3+5x Solve for x

Mathematics

2 answers:

astra-53 [7]3 years ago

5 0

Answer:

x=3/7

Step-by-step explanation:

bring -2x to the other side and add to 5x to get 7x. bring 3 to the other side and subtract by 6 to get 3. now it's 3=7x. divide both sides by 7 and get x=3/7

evablogger [386]3 years ago

3 0

Answer:

x=3/7

Step-by-step explanation:

6-2x=3+5x

subtract 5x from both sides

6-2x-5x=3

subtract 6 from both sides

-2x-5x=3-6

add like terms

-7x=-3

divide both sides by -7

x=3/7

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the sum of 2 numbers is 49. Twice the smaller number is 97 less than 3 times the larger number. What are the numbers?

ivanzaharov [21]

Answer:

let the larger and smaller number be x and y respectively

first condition

x + y = 49

second condition

3x = 2y+97

3x-2y =97

Multiplying first condition by two and adding both equations

2x + 2y = 98

5x = 195

x = 195/5 = 39

putting the value of x in

x + y = 49

y = 49 -39 = 10

again

Step-by-step explanation:

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3 years ago

What is the slope of the line <br> -3x+5y=2x+3y

GaryK [48]

X=2/5y
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8 0

3 years ago

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What is the best approximation for relative maximum of the polynomial function graphed below?

AlexFokin [52]

A. (0.6, -2.8)

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3 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago

Help please-<br> Ty :DDD

photoshop1234 [79]

Answer:

Step-by-step explanation:

6 0

3 years ago

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