The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²
Add them all up to get it
Answer:
yes
Step-by-step explanation:
it's saying pretty much take 15 out of 38
Answer:
3x² – 2x – 8
=> 3x² – 6x + 4x – 8
=> 3x( x – 2 ) + 4( x – 2 )
=> ( 3x + 4 ) ( x – 2 )
Therefore,
Either, 3x + 4 = 0
3x = - 4
x = - 4/3 (Ans)
And,
x – 2 = 0
x = 2 (Ans)
The length of the hypotenuse = √(-3^2 +1^2) = √10
The point -3,1 tell us the length of y is 1 and the length of x is 3.
This would make opposite = 1 and adjacent = -3
Sinθ = opposite/hypotenuse = 1/√10 = √10/10
Cosθ = adjacent/hypotenuse = -3/√10 = - 3√10/10
Tanθ = opposite/adjacent = 1/-3 = -1/3