HELPP I NEED HELP!!!

pishuonlain [190]

Answer:

y-10=2/3(x-8)

Step-by-step explanation:

(y2-y1)/(x2-x1) is the equation for slope so put your points in you get 2/3 once simplified then its just a matter of putting points in the equation y-y1= m(x-x1)

5 0

3 years ago

PLZ HELP, GIVING BRAINLIEST!

mote1985 [20]

Answer:

d) (-3/2, -1/2)

Step-by-step explanation:

The midpoint (M) between two given points is the average of their coordinate values:

M = (A + B)/2 = ((-8, 1) +(5, -2))/2 = (-3, -1)/2

M = (-3/2, -1/2) . . . . . matches choice D

4 0

3 years ago

What does 6-2p+5p-3 equal

viva [34]

Answer:

3 + 3p

Step-by-step explanation:

since there's no equal sign or no value that it shows all of that added together is equivalent to it's not really equal to anything. However if you're asking what that equation would look like if you simplified it down , then it would be 3 + 3p because you combine the like terms

4 0

3 years ago

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While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between

aleksandr82 [10.1K]

Answer:

The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

Step-by-step explanation:

Let the random variable X denote the water depths.

As the variable water depths is continuous variable, the random variable X follows a continuous Uniform distribution with parameters a = 2.00 m and b = 7.00 m.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

$P(2.25$

$=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55$

Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

6 0

3 years ago

Determine if the following infinite series converges or diverges

Mandarinka [93]

Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.

<h3>How do we verify if a sequence converges of diverges?</h3>

Suppose an infinity sequence defined by:

$\sum_{k = 0}^{\infty} f(k)$

Then we have to calculate the following limit:

$\lim_{k \rightarrow \infty} f(k)$

If the limit goes to infinity, the sequence diverges, otherwise it converges.

In this problem, the function that defines the sequence is:

$f(k) = \frac{k^3}{k^4 + 10}$

Hence the limit is:

$\lim_{k \rightarrow \infty} f(k) = \lim_{k \rightarrow \infty} \frac{k^3}{k^4 + 10} = \lim_{k \rightarrow \infty} \frac{k^3}{k^4} = \lim_{k \rightarrow \infty} \frac{1}{k} = \frac{1}{\infty} = 0$

Hence, the infinite sequence converges, as the limit does not go to infinity.

More can be learned about convergent sequences at brainly.com/question/6635869

#SPJ1

6 0

1 year ago

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