For numbers 1a - 1c, circle YES or NO for each statement using the table below.

Help please please answer

kogti [31]

Answer:

A

Step-by-step explanation:

x. y = 28

check attachment

4 0

3 years ago

What is the volume of a rectangular prism with a length of 2 inches, a width of an inch & is a quarter of an inch in height?

irina1246 [14]

Answer:

Step-by-step explanation:

Right rectangular prism

Solve for volume

V=whl

l Length

2

Width

Height

6 0

3 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

3 years ago

How many distinguishable 7 letter "words" can be formed using the letters in alabamaalabama?

otez555 [7]

You are given the word alabama and you are asked to find how many distinguishable 7 letter "words" can be formed from it.

ALABAMA has seven letters so we will start at 7!
Counting the number of A's in the word we have 4 A's and so we will divide it by 4!
Counting the number of L's in the word we have 1 L and so we will divide it by 1!
Counting the number of B's in the word we have 1 B and so we will divide it by 1!
Counting the number of M's in the word we have 1 M and so we will divide it by 1!

And so the number of ways is 7! / (4! x 1! x 1! x 1!) = 210 words.

3 0

4 years ago

I need to know this what is 4.75 as a fraction can someone help

WINSTONCH [101]

Answer:

4 $\frac{3}{4}$

Step-by-step explanation:

so we see a wholoe number "4", lets set that aside

we are left with 0.75 right

we can also write this as

75/100

we can simplify this by dividing 25 on both sides so it will becocme:

3/4

*Remember we have to bring the "4" we set aside earlier so final answer is*

4 and 3/4

8 0

3 years ago