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IRINA_888 [86]
3 years ago
8

Find the area of the triangle to the nearest tenth.

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Answer:

It C

Step-by-step explanation:

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Use the quadratic formula to find the solution to the quadratic equation in the box below.
nekit [7.7K]
The solution to the quadratic equation is option D
4 0
3 years ago
Factorize (x-3)(x-5)(x-7)(x-9)+15
zhannawk [14.2K]

The expanded form of the equation is x^4-24x^3+222x^2-240+960

<h3>Expansion of expression</h3>

Given the expression below;

(x-3)(x-5)(x-7)(x-9)+15

Expand

(x-3)(x-5)(x-7)(x-9) + 15

(x^2-5x-3x+15)(x^2-9x-7x+63) +15

(x^2-8x+15)(x^2-16x+63) + 15

Expand further to have;

x^4-16x^3+63x^2-8x^3+144x^2-504+15x^2-240x+945+15

x^4-24x^3+222x^2-240+960

Hence the expanded form of the equation is x^4-24x^3+222x^2-240+960

Learn more on expansion here: brainly.com/question/29114
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6 0
2 years ago
What is the solution to the equation?
KonstantinChe [14]
Answer: D
1/2x-1+4=x
1/2x-x=-3
-1/2x=-3
x=6
4 0
3 years ago
Read 2 more answers
What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?
tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

y=x^{2}-8x+15

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

x^{2}-8x+15=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-8x+15=0  

so

a=1\\b=-8\\c=15

substitute in the formula

x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}

x=\frac{8\pm\sqrt{4}} {2}

x=\frac{8\pm2} {2}

x=\frac{8+2} {2}=5

x=\frac{8-2} {2}=3

so

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0
3 years ago
Use the variable d to represent the unknown quantity. the product of 4 and the depth of the pool
natka813 [3]

This can be represented by the expression 4d.

6 0
2 years ago
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