Answer:
1
Step-by-step explanation:
We know that the mathematics test scores are normally distributed with mean μ=82 and standard deviation σ=8.
We know that the central limit theorem states that a selected sample from a normal distribution with mean μ and standard deviation σ is also normally distributed with mean μxbar and standard deviation σxbar.
Also , the sample mean of sampling distribution is μxbar=μ, where μ is population mean.
The standard deviation of sampling distribution is σxbar=σ/√n where n is the sample size and σ is population standard deviation.
The given sample size=n=64.
So, the required standard deviation of sampling distribution is
σxbar=σ/√n
σxbar=8/√64
σxbar=8/8
σxbar=1.
Answer:
Step-by-step explanation:
i don't see the thing you put it just shows the question
