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juin [17]
3 years ago
12

I am a one digit number. Follow the calculation steps and Find me.

Mathematics
1 answer:
artcher [175]3 years ago
5 0

Answer:

8

Step-by-step explanation:

First, let’s say the number is x

Then follow the steps

12x+6

36x+18

36x+9

12x+3=99

So x=8

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A map has a scale of 3 cm: 18 km. If Riverside and Smithville are 54 km apart then how many cm is that on a map?
Sladkaya [172]

Answer:

9 cm

Step-by-step explanation:

If the scale is 3cm:18 km, then x cm : 54km will be the distance between Riverside and Smithville. Since 18 *3 = 54 then 3cm * 3 = 9cm. On the map they are 9 cm apart.


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Help ASAP geometry !
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
A small metal bar, whose initial temperature was 10° C, is dropped into a large container of boiling water. How long will it tak
IgorC [24]

Answer

According to newton law of cooling

\dfrac{d T}{dt} = k (T - T_a)

and

T = Ce^{kt} + T_a

now At Ta = 100

T₀ = 10 °C

T₁ = 12° C

T(0) = Ce^{0} + T_a

10 = C + 100

C = -90

now,

12 = -90e^k + 100

e^k = \dfrac{88}{90}

k = ln{\dfrac{88}{90}}

at time equal to t

T(t) = 70

T(t) = -90 (\dfrac{88}{90})^t + 100

70 = -90(\dfrac{88}{90})^t + 100

(\dfrac{88}{90})^t = \dfrac{1}{3}

t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{3})

t = 48.88 s

hence, after 48.88 s the temperature of the body will be 70°C

b) time taken to reach 98°C

T(t) = -90 (\dfrac{88}{90})^t + 100

98 = -90(\dfrac{88}{90})^t + 100

(\dfrac{88}{90})^t = \dfrac{1}{45}

t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{45})

t = 390 s

hence, after 390 s the temperature of the body will be 98°C

5 0
3 years ago
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