.25(4) = 1 gallon
.25(8) = 2 gallons
.25(12) = 3 gallons
.25(16) = 4 gallons
.25(20) = 5 gallons
it would take 20 minutes to remove half the water (aka 5 gallons)
Answer:
53%
Step-by-step explanation:
use formula: (new value - original value) / original value and you will get .533 which rounds to 53%
Answer:
The answer is below
Step-by-step explanation:
The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the answers to 3 decimal places.
(a) What is the probability that more than three aircraft arrive within an hour?
(b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals?
(c) Determine the length of an interval of time (in hours) such that the probability that no arrivals occur during the interval is 0.1.
Solution:
a) A poisson distribution is given by the formula:

λ = 1 hour
Therefore:
P(X > 3) = 1 - P(X < 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(x = 3)]




P(X > 3) = 1 - [0.3679+0.3679 + 0.1839 + 0.0613] = 0.019
b) Assuming 30 1 hour intervals, hence:
![P(X \leq 3)^{30}=[1-P(X\geq 30)]^{30}=(1-0.019)^{30}=0.5624](https://tex.z-dn.net/?f=P%28X%20%5Cleq%203%29%5E%7B30%7D%3D%5B1-P%28X%5Cgeq%2030%29%5D%5E%7B30%7D%3D%281-0.019%29%5E%7B30%7D%3D0.5624)
c) mean = 1 hour
mean = 1 / λ
1 = 1 / λ
λ = 1
The cumulative distribution function of a continuous variable is:


It would be = -3.23 * 10^15
Answer:
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