Answer:
1/2
Explanation:
<em>Turner syndrome is a monosomy condition - a condition in which the victim lacks a chromosome. The condition is caused by a normal gamete fusing with a gamete that lacks a chromosome as a result of nondisjunction during meiosis.</em>
When the gametes of a man undergo nondisjunction, two types of gametes are produced - OY gametes and XXY gametes. In order to produce a child with Turner syndrome (XO), the OY gamete of the man must have participated with a normal XX female gamete.
OY x XX
XO XO XY XY
<em>Hence, the probability of producing a </em><em>XO</em><em> child = 2/4 of 1/2</em>
If the XXY gamete participate in fertilization,
XXY x XX
XXX XXX XY XY
XXX females would be produced instead of XO children.