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taurus [48]
3 years ago
7

Please help!!fully simplify

3%7D%20%7D%7B%5Csqrt%7B108%7D%20%7D" id="TexFormula1" title="\frac{\sqrt{300}+\sqrt{27}-\sqrt{3} }{\sqrt{108} }" alt="\frac{\sqrt{300}+\sqrt{27}-\sqrt{3} }{\sqrt{108} }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
AleksandrR [38]3 years ago
7 0
The answer is 2
you will simplify the expression to 10 square root 3 + 3 square root 3 - square root 3 over square root 108. the collect the like terms which will be 12 square root 3 over square root 108. the simplify the expression which will be 12 over square root 36. calculate the square root in the denominator which is 6. 12/6 is 2
bija089 [108]3 years ago
6 0

Answer:

The answer is 2

Step-by-step explanation:

Multiply the numerator and denominator by the conjugate.

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Read 2 more answers
The answer below thanks
Greeley [361]

Answer:

The equation of the circle having centre (-5,-9) and radius r=3  is

x² + 10 x +y² + 14 y + 65 = 0

Step-by-step explanation:

<u>Explanation</u>:-

From graph  The centre of the circle  C( -5 , -7)

The radius of the circle r = 3cm from the centre of the given circle

The equation of the circle



From graph the centre ( h, k) = ( -5,-7) and r = 3cm

                 (x-(-5))^2+(y-(-7))^2 = 3^2

                x² + 10 x +25 +y² + 14 y + 49 =9

              x² + 10 x +25 +y² + 14 y + 49 -9=0

 The equation of the circle

                x² + 10 x  +y² + 14 y + 65 = 0  

 



                     

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