-- The smallest perimeter you can make with a certain area
is a circle.
-- The NEXT smallest perimeter with the same area is a square.
With 1-ft by 1-ft square bricks, the shortest perimeter she could
make would be by using her bricks to make it as square as possible.
Without cutting bricks into pieces, the best she could do would be
(13 bricks) x (3 bricks) .
= (13-ft) x (3-ft)
Perimeter = (2 x length) + (2 x width)
= (2 x 13-ft) + (2 x 3-ft)
= (26-ft) + (6-ft) = 32 feet <== shortest perimeter.
-- Then, the more UNSQUARE you make it, the more perimeter
it takes to enclose the same area. That means Mary has to make
a rectangle as long and skinny as she can.
The longest perimeter she can make (without cutting bricks into
pieces) is (39 bricks) x (1 brick) .
= (39-ft) x (1-ft) .
Perimeter = (2 x length) + (2 x width)
= (2 x 39-ft) + (2 x 1-ft)
= (78-ft) + (2-ft) = 80 feet .
What she'll have then is a brick path, 39 feet long and 1 foot wide,
and when you walk on it, you'll need to try hard to avoid falling off
because it's only 1 foot wide.
The building is 24 (whatever’s you want ex. Meters, Feet) high. Because 38.7=tan^-1(height/30). Or cos(38.7)=30/hypotenuse. Hypotenuse=30/cos(38.7
Answer:
The answer is below
Step-by-step explanation:
The profit equation is given by:
p(t)= -25t³+625t²-2500t
The maximum profit is the maximum profit that can be gotten from selling t trailers. The maximum profit is at point p'(t) = 0. Hence:
p'(t) = -75t² + 1250t - 2500
-75t² + 1250t - 2500 = 0
t = 2.3 and t = 14.3
Therefore t = 3 trailers and t = 15 trailers
p(15) = -25(15³) + 625(15²) - 2500(15) = 18750
Therefore the company makes a maximum profit of approximately $18750 when it sells approximately 15 trailers.
We are asked to find the equivalent of the expression given:
(3m⁻² n)⁻³
-----------
6mn⁻²
Perform distribution of power using power rule such as shown below:
3⁻³ m⁻²*⁻³n⁻³
-----------------
6mn⁻²
Perform product and quotient rule such as shown below:
m⁶ n²
--------
3³ *6*m*n³
Simplify,
m⁵
--------
162n
The answer is m⁵/162n.