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2 years ago

5

Lashonda has bought 18 pounds of dog food. She feeds her dog 2/3 pounds for each meal. For how many meals will the food last? Wr

ite your answer in simplest form.

1 answer:

vesna_86 [32]2 years ago

6 0

Answer:

she have feed 26 or 27

Step-by-step explanation:

I am confused it's 26 or27

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Convert 96.4% to a fraction in simplest form and a decimal.

GREYUIT [131]

Answer:

241/250

Step-by-step explanation:

5 0

3 years ago

Simplify the expression.

Nimfa-mama [501]

The answer is C.15c+72

5 0

3 years ago

15. PLEASE HELP ME

Nana76 [90]

Surface Area=7238in^2

We know

$\boxed{\sf Surface\:area=4\pi r^2}$

$\\ \sf\longmapsto 4\pi r^2=7238$

$\\ \sf\longmapsto 4\times \dfrac{22}{7}r^2=7238$

$\\ \sf\longmapsto r^2=\dfrac{7238\times 7}{88}$

$\\ \sf\longmapsto r^2=\dfrac{5066}{88}$

$\\ \sf\longmapsto r^2=575.75$

$\\ \sf\longmapsto r^2\approx576$

$\\ \sf\longmapsto r\approx\sqrt{576}$

$\\ \sf\longmapsto r\approx24in$

<h3>Option b is coreect</h3>

4 0

3 years ago

Read 2 more answers

If three pears and four oranges cost $4.85 and three pears and ten oranges cost $8.75 what is the cost of a pear and an orange

marishachu [46]

Answer:

1 pear = $0.75; 1 orange = $0.65

Step-by-step explanation:

(1) 3P + 4O = 4.85

(2) 3P + 10O = 8.75 Eqn (2) - Eqn (1)

3P + 10O – 3P – 4O = 8.75 – 4.85 Combine like terms

6O = 3.90 Divide each side by 6

O = $0.65 Substitute into Eqn (1)

3P + 4×0.65 = 4.85

3P + 2.60 = 4.85 Subtract 2.60 from each side

3P = 2.25 Divide each side by 3

P = $0.75

Oranges cost $0.65 each and pears are $0.75 each

4 0

3 years ago

the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.

suter [353]

Answer:

The width of the photo is $4w^2+6w+4$ .

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

$6w^2+8$

The photo is covered by a frame border and the width of the border is

$w^2-3w+2$

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

$\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})$

$\text{Width of the photo}=6w^2+8-2(w^2-3w+2)$

$\text{Width of the photo}=6w^2+8-2w^2+6w-4$

$\text{Width of the photo}=4w^2+6w+4$

Therefore the width of the photo is $4w^2+6w+4$ .

4 0

3 years ago