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Tju [1.3M]
3 years ago
5

131.136 divided by 4

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0

Answer:

32.784

Step-by-step explanation:

that is the answer

jarptica [38.1K]3 years ago
6 0

Answer:

32.784

Step-by-step explanation:

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What is a comparison as a rate in ratio form 70 students per 2 teachers​
nekit [7.7K]

Answer:

35:1

Step-by-step explanation:

divide each by two

8 0
3 years ago
The math department sold pie slices to buy new math books. Two pies were contributed by members of the department. Each pie was
kenny6666 [7]
The answer is 8, just divide 6 by 48. Hope it helped.
8 0
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Jen fills her has tank up with 12 gallons of gas for $30.60. How much will it cost to fill up a 17-gallon tank?
tigry1 [53]

Answer:

$43.35 (I believe)

Step-by-step explanation:

I tried to find the price to fill up 1 gallon by dividing the $30.60 by 12. 30.6/12 = 2.55 and then I multiplied $2.55 by 17 and got $43.35

4 0
3 years ago
A billing company that collects bills for​ doctors' offices in the area is concerned that the percentage of bills being paid by
omeli [17]

Answer:

1) A. H0: p = 0.30

HA: p not equal to 0.30

2) A. The Independence Assumption is met.

C. The Randomization Condition is met.

D. The Success/Failure Condition is met.

3) Test statistic z = 2.089

P-value = 0.0367

4) C. Reject H0. There is sufficient evidence to suggest that the percentage of bills paid by medical insurance has changed.

Step-by-step explanation:

1) This is a hypothesis test for a proportion.

The claim is that there is a significant change in the percent of bills being paid by medical​ insurance.

As we are looking for evidence of a difference, no matter if it is higher or lower than the null hypothesis proportion, the alternative hypothesis is defined by a unequal sign.

Then, the null and alternative hypothesis are:

H_0: \pi=0.3\\\\H_a:\pi\neq 0.3

2) Cheking the conditions:

The independence assumption and the randomization condition are met as the bills were selected randomly from the population.

The 10% condition can not be checked, as we do not know the size of the population.

The success/failure condition is met as the products np and n(1-p) are bigger than 10 (the number of successes and failures are both bigger than 10).

3) The significance level is assumed to be 0.05.

The sample has a size n=9260.

The sample proportion is p=0.31.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.3*0.7}{9260}}\\\\\\ \sigma_p=\sqrt{0.000023}=0.005

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.31-0.3-0.5/9260}{0.005}=\dfrac{0.01}{0.005}=2.089

This test is a two-tailed test, so the P-value for this test is calculated as:

\text{P-value}=2\cdot P(z>2.089)=0.0367

As the P-value (0.0184) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that there is a significant change in the percent of bills being paid by medical​ insurance.

5 0
3 years ago
Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you
dalvyx [7]

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

3 0
3 years ago
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