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Charra [1.4K]
3 years ago
13

There is 3/4 of a pizza leftover from the night before. How many 1/8 portions are there?

Mathematics
2 answers:
asambeis [7]3 years ago
8 0
Divide 3/4 by 1/8
3/4 as a decimal is .75, and 1/8 as a decimal is .125. Divide those and you get 6 
So 6 is your answer
Andrew [12]3 years ago
7 0
There would be 6 slices left
You might be interested in
Solve for the unknown variables
malfutka [58]

Answer:

This term is known as algebra.

Step-by-step explanation:

Algebra is all about solving for unknown values. Of course, in the primary phrase (question) it says, "Solve for the unknown variables," and the unknowns are unknown variables that have values that are unknown and must be found through algebraic processes.  

<h2>What is an "algebra" in mathematics?</h2>

Variables like as x, y, and z are coupled with mathematical operations such as addition, subtraction, multiplication, and division to generate a meaningful mathematical statement. An algebraic expression is as basic as 2x + 4 = 8. Algebra is concerned with symbols, and these symbols are connected to one another through operators. It is more than just a mathematical concept; it is a skill that we all have without even realizing it. Understanding algebra as a concept is more important than solving equations and achieving the proper solution since it applies to all other disciplines of mathematics that you will learn or have previously learned.

<h3>What is Algebra?</h3>

Algebra  is a field of mathematics that works with symbols and the mathematical operations that may be performed on them. These symbols, which have no set values, are referred to as variables. We frequently encounter values that change in our real-life issues. However, there is a continual requirement to represent these changing values. In algebra, these values are frequently represented by symbols such as x, y, z, p, or q, and these symbols are referred to as variables. Furthermore, these symbols are subjected to different mathematical operations such as addition, subtraction, multiplication, and division in order to determine the values. 3x + 4 = 28. Operators, variables, and constants are used in the algebraic formulas above. The integers 4, 28, and x are constants, and the arithmetic operation of addition is done. Algebra is a branch of mathematics concerned with symbols and the mathematical operations that may be applied to them. Variables are symbols that do not have predefined values. In our daily lives, we regularly face values that shift. However, there is a constant need to express these shifting values. These values are usually represented in algebra by symbols such as x, y, z, p, or q, and these symbols are known as variables. Furthermore, in order to ascertain the values, these symbols are subjected to various mathematical operations such as addition, subtraction, multiplication, and division. 3x + 4 = 28. The algebraic formulae above make use of operators, variables, and constants. The constants are the numbers 4, 28, and x, and the arithmetic operation of addition is done.

<h3>Branches of Algebra</h3>

The use of many algebraic expressions lessens the algebraic complexity. Based on the usage and complexity of the expressions, algebra may be separated into many branches, which are listed below:

Pre-algebra: The basic methods for expressing unknown values as variables help in the formulation of mathematical assertions. It facilitates in the transition of real-world problems into mathematical algebraic expressions. Pre-algebra entails creating a mathematical expression for the given problem statement.

Primary algebra: Elementary algebra is concerned with resolving algebraic expressions in order to arrive at a viable solution. Simple variables such as x and y are expressed as equations in elementary algebra. Based on the degree of the variable, the equations are classed as linear, quadratic, or polynomial. The following formulae are examples of linear equations: axe + b = c, axe + by + c = 0, axe + by + cz + d = 0. Primary algebra can branch out into quadratic equations and polynomials depending on the degree of the variables.

<h3>Algebraic Expressions</h3>

An algebraic expression is made up of integer constants, variables, and the fundamental arithmetic operations of addition (+), subtraction (-), multiplication (x), and division (/). An algebraic expression would be 5x + 6. In this situation, 5 and 6 are constants, but x is not. Furthermore, the variables can be simple variables that use alphabets like x, y, and z, or complicated variables that use numbers like

x^2,x^3,x^n,xy,x^2y,

and so forth. Algebraic expressions are sometimes known as polynomials. A polynomial is a mathematical equation that consists of variables (also known as indeterminates), coefficients, and non-negative integer variable exponents. As an example,

5x^3+4x^2+7x+2=0

Any equation is a mathematical statement including the symbol 'equal to' between two algebraic expressions with equal values. The following are the many types of equations where we employ the algebra idea, based on the degree of the variable: Linear equations, which are stated in exponents of one degree, are used to explain the relationship between variables such as x, y, and z. Quadratic Formulas: A quadratic equation is usually written in the form

ax^2+bx+c=0,

7 0
2 years ago
Probability. A professor rides his bike to work some days and drives his car on the other days. On any day there is an 80% chanc
Artyom0805 [142]

Answer:

0.09

Step-by-step explanation:

Given :

P(bike) = 0.8

P(car) = 0.2

P(Late given car) = P(Late | car) = 0.05

P(Late given bike) = p(Late | bike) = 0.1

Probability that professor is late :

P(late) = [P(Late | car) * p(car)] + [p(Late | bike) * p(bike)]

P(late) = [0.05 * 0.2] + [0.1 * 0.8]

P(late) = 0.01 + 0.08

P(late) = 0.09

3 0
3 years ago
Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-10, 12) and point (5, 3) rounded
Whitepunk [10]

Answer:

<h3>The answer is 17.5 units</h3>

Step-by-step explanation:

Using the distance formula

<h3>d =  \sqrt{ ({x2 - x1})^{2} +  ({y2 - y1})^{2}  }</h3>

the distance between (-10, 12) and (5, 3) is

<h3>d =  \sqrt{ ({5 + 10})^{2}  +  ({3 - 12})^{2} }</h3><h3>d =  \sqrt{ {15}^{2}  + ( { - 9})^{2} }</h3><h3>d =  \sqrt{225 + 81}</h3><h3>d =  \sqrt{306}</h3><h3>d = 3 \sqrt{34}</h3>

d = 17.492855

We have the final answer as

<h3>d = 17.5 units to the nearest tenth</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
In a certain soccer tournament you are playing once with each of the other nine teams. In every match you get 3 points if you wi
bixtya [17]

Answer:

0.430625=0.431

Step-by-step explanation:

Answer:

0.430625 = 0.431

Step-by-step explanation:

Let W represent winning, D represent a draw and L represent a loss.

12+ points can be garnered in each of the following ways.

6W 0D 0L

5W 1D 0L

5W 0D 1L

4W 2D 0L

4W 1D 1L

4W 0D 2L

3W 3D 0L

The probability of getting 12+ points is the sum of all these 7 probabilities.

Knowing that P(W) = 0.5

P(D) = 0.1

P(L) = 0.4

P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625

P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875

P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075

P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375

P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075

P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15

P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025

The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625

Read more on Brainly.com - brainly.com/question/14850440#readmore

4 0
3 years ago
What is the simplified form of the quantity y-squared plus 7y plus 12 over the quantity y-squared plus 8y plus 15
Burka [1]
Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.

7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)

Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.

Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.

This gives us our final answer:
(y+4)/(y+5)
8 0
4 years ago
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