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3 years ago

I have 2 questions. Please help! I will mark the Brainliest for the best answer(s)

2 answers:

8 0

1. Jane has $40 to begin with
Fay has $32 to begin with
Henry has $18 to begin with

They all end with the same amount which must be 30.

40-12=28.- Jane 18+12=30- Henry
32-2=30-Fay. 28+2=30

2. 240+241+242= 723

polet [3.4K]3 years ago

5 0

Answer:

1. J=20, f= 28, H=42

2. 240 + 241 + 242 = 723

Step-by-step explanation:

J= 30- 12= 18+2= 20

F= 30-2=28

H=30+12=42

240 + 241 + 242 = 723

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Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is

Sedaia [141]

Answer:

x + y = 29, 5x + 2y = 100

Step-by-step explanation:

First, create an equation based on how there are 29 problems on the test.

x + y represents all of the questions on the test, so it should be set equal to 29.

The first equation is x + y = 29.

Now, create an equation based on how the test is worth 100 points.

5x will represent the points from the questions worth 5 points, and 2y will represent the points from the questions worth 2 points.

These terms will be added together, and set equal to 100.

The second equation is 5x + 2y = 100.

So, the system of equations is x + y = 29, 5x + 2y = 100

8 0

3 years ago

Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,

stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0

3 years ago

What are the solutions of the equation

Snowcat [4.5K]

C^2 - 10c = 0
c^2 - 10c + 25 = 25
(c - 5)^2 = 25
c - 5 = sqrt 25
c = 5 (+-) sqrt 25
c = 5 (+-) 5

c = 5 + 5 = 10
c = 5 - 5 = 0

solutions are 0,10

3 0

4 years ago

the length of a rectangle is 61/2 inches and the width is 33/4,. what is the ratio, using whole numbers of the length to the wid

xxTIMURxx [149]

61/2 inches = 30.5 inches

33/4 inches = 8.25 inches

----------------

$8.25\times n=30.5\\ \\ \therefore \quad n=\frac { 30.5 }{ 8.25 } =\frac { 122 }{ 33 }$

----------------

Ratio:

122/33 : 1

= 122/33 x 33 : 1 x 33

= 122:33

5 0

4 years ago

1.64 divide by 22 I don’t even know this help me?

Sergeeva-Olga [200]

The answer would be 7.54

8 0

3 years ago