Answer:
Possible C:
(1 , 1 + 3sqrt(3))
(1 , 1 - 3sqrt(3))
Step-by-step explanation:
AB = 6 units
Midpoint of AB is (1,1)
C would be at x = 1
So, (1,y)
(y-1)² + (1+2)² = 6²
(y-1)² = 36 - 9
(y-1)² = 27
y - 1 = 3sqrt(3)
y - 1 = -3sqrt(3)
y = 1 + 3sqrt(3)
y = 1 - 3sqrt(3)
Answer:
The indefinite integral
=
ˣ
⁺ C
Step-by-step explanation:
x= 10sinθ
dx = 10cosθdθ
the step-to-step explanation is in the attachment
Well, i don't know what you're asking, but -11,2,7,8,22?